1. when x⇒∞, y=∞ and when x⇒-∞, y=-∞
So, we have a odd degree polynomial (x³ or 
or even 
).
The leading coefficient is negative its end behavior matches x³ which has a positive leading coefficient.
2. when x⇒∞, y=∞ and when x⇒-∞, y=∞
So, we have a even degree polynomial (x² or 
or even 
).
And because it matches these parent functions listed above (they all have positive leading coefficients), the leading coefficient is again positive.
answers:
1. odd and positive
2. even and positive
Answer:
The expression is equivalent , but is not completely factored
Step-by-step explanation:
A student factors 3x² – 12 to the following. 3(x² – 4)
3x² – 12 is equivalent to 3(x² – 4), because 3 was factored out;
If we multiply by 3 by opening the brackets then we get the same expression 3x² – 12.
However; <em>3(x² – 4), could be factored further;</em>
<em>To get; 3(x + 2)(x - 2) ; since x² – 4 is a difference of two squares;</em>
<em>Therefore;</em>
<em>3x² – 12 = 3(x² – 4) = 3(x + 2)(x - 2)</em>
Answer:
66.6666666667
Step-by-step explanation:
answer is 66.6666666667
For this problem, the answer is choice A.
Answer:
the slope is 2/3 bcoz u do 2-0/3-0
