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nignag [31]
3 years ago
7

PLEASE HELP ME ASAP???!!!!!!!!

Mathematics
1 answer:
Ivenika [448]3 years ago
8 0

Answer:

I'm very very sorry I cannot help you I wish I could help sorry bud.

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Plz help
frozen [14]

Answer:

a. Required system of equations is:

c+p = 10

5c+4p = 46

b. 6 cakes were sold

Step-by-step explanation:

Let p be the number of pies and c be the number of cakes.

Then according to given statement " the store sold 10 baked goods"

c+p = 10\ \ \ Eqn\ 1

And

"A cake costs $5 and a pie costs $4"

5c+4p = 46\ \ \ \ Eqn\ 2

Using equation 1,

c=10-p

Putting this value of c in equation 2:

5(10-p)+4p = 46\\50-5p+4p = 46\\-p = 46-50\\-p = -4\\p = 4

Putting p = 4 in equation 1

c+4 = 10\\c = 10-4\\c =6

Hence,

a. Required system of equations is:

c+p = 10

5c+4p = 46

b. 6 cakes were sold

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3 years ago
In the figure, ABCD is a parallelogram and its area 15<br>48 cm". Find DM and DN.​
matrenka [14]

More information is needed to solve the problem.

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3 years ago
MATH 15 POINTS, HELP
7nadin3 [17]
Statement 3: tri egc = tri egb
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3 years ago
F(x)=2x^2 -5 , simplify f(x+h)/h , where h≠0
7nadin3 [17]

Answer:

\huge\boxed{\dfrac{f(x+h)}{h}=\dfrac{2x^2+4xh+2h^2-5}{h}}

\huge\boxed{\dfrac{f(x+h)}{h}=\dfrac{2x^2-5}{h}+4x+2h}

Step-by-step explanation:

f(x)=2x^2-5\\\\\dfrac{f(x+h)}{h}=\dfrac{2(x+h)^2-5}{h}=\dfrac{2(x^2+2xh+h^2)-5}{h}\\\\\dfrac{f(x+h)}{h}=\dfrac{2x^2+4xh+2h^2-5}{h}\\\\h\neq0

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