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AleksAgata [21]
3 years ago
6

Plz help

Mathematics
1 answer:
frozen [14]3 years ago
7 0

Answer:

a. Required system of equations is:

c+p = 10

5c+4p = 46

b. 6 cakes were sold

Step-by-step explanation:

Let p be the number of pies and c be the number of cakes.

Then according to given statement " the store sold 10 baked goods"

c+p = 10\ \ \ Eqn\ 1

And

"A cake costs $5 and a pie costs $4"

5c+4p = 46\ \ \ \ Eqn\ 2

Using equation 1,

c=10-p

Putting this value of c in equation 2:

5(10-p)+4p = 46\\50-5p+4p = 46\\-p = 46-50\\-p = -4\\p = 4

Putting p = 4 in equation 1

c+4 = 10\\c = 10-4\\c =6

Hence,

a. Required system of equations is:

c+p = 10

5c+4p = 46

b. 6 cakes were sold

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