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Nesterboy [21]
3 years ago
8

Please help me with this question.

Mathematics
1 answer:
JulsSmile [24]3 years ago
6 0

Answer:

<h2>The graph in the attachment.</h2><h2>The inverse is not a function.</h2>

Step-by-step explanation:

The graph of the function and its inverse are symmetric with respect to the line y = x.

The inverse is not a function because for x = 3 we has two values of y: -3 and -4 (look at the picture).

<em>A function is a relation that associates each element x of a set X to a single element y of another set Y.</em>

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Can anyone help me solve this?​
Alecsey [184]

Answer:

Step-by-step explanation:

(\sqrt{z} +\sqrt{22})(\sqrt{z} -\sqrt{22})=35

Subtract both sides from 35

(\sqrt{z}+\sqrt{22} (\sqrt{z} -\sqrt{22})-35=35-35

Simplify:

(\sqrt{z})^{2} -57=0

Factor (\sqrt{z})^{2}  -57: (\sqrt{z}+\sqrt{57}) (\sqrt{z}-\sqrt{57})=0

\sqrt{z} +\sqrt{57}=0    or    \sqrt{z}  -\sqrt{57}=0

\sqrt{z} +\sqrt{57} =0: No Solution for Z

\sqrt{z} -\sqrt{57} =0: z=57

Your answer will be z=57

and No solution

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2 years ago
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Answer: same

Step-by-step explanation:

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nlexa [21]

Answer:

Step-by-step explanation:

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3 years ago
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What is the sum of 7 3/16+3/4​
muminat

Answer:

7 15/16

Step-by-step explanation:

find the same denominator which is 16

3/4x4/4 = 12/16

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probably bad explanation but hope it helps.. :)

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2 years ago
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Avery and Carmen both have summer jobs. Avery gets paid 360 bucks every 4 weeks, how much money does she make in one week.
artcher [175]

Avery gets paid 90 bucks per week

Step-by-step explanation:

The per month payment is obtained by dividing the whole amount by time.

Given

Avery gets paid 360 for 4 weeks

In order to find her payment for one week, we have to divide the total amount by 4 to get the payment for one week

So,

One\ week's\ payment = \frac{Total\ payment}{number\ of\ weeks}\\=\frac{360}{4}\\= 90

Avery gets paid 90 bucks per week

Keywords: Unit price, payment

Learn more about unit price at:

  • brainly.com/question/2455974
  • brainly.com/question/2451812

#LearnwithBrainly

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