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Sidana [21]
3 years ago
12

a card is chosen from a standard deck, then a month of the year is chosen. find the probability of getting a face card and june​

Mathematics
1 answer:
Irina-Kira [14]3 years ago
4 0

Answer:

Probability of chossing a face card and the month of june = 0.019

Step-by-step explanation:

Let A be the event that a face card is chosen from a deck of 52 cards

And

B be the event that a month is being chosen from 12 months of an year

So,

n(S)for A=52

n(S)for B=12

As a deck of card has total of 12 face cards so

P(A)=12/52

=3/13

P(B)=1/12

As both the events are independent, the probability of A and B is the product of both events’ probabilities.

P(A and B)= P(A)*P(B)

=3/13*1/12

=3/156

=0.019

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3 years ago
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I don't know what to do. This is about odd and even functions.
Alexxandr [17]

Answer:

C.

Step-by-step explanation:

We are given f,g are odd which means:

f(-x)=-f(x)

g(-x)=-g(x)

We can tell if a function,h, is even if h(-x)=h(x).

We can tell if a function,h, is odd if h(-x)=-h(x).

So let's test your I,II,III.

We will be replacing x with -x to find out.

I.

p(x)=f(g(x))

p(-x)=f(g(-x))

p(-x)=f(-g(x))

p(-x)=-f(g(x))

p(-x)=-p(x)

So p is odd.

II

r(x)=f(x)+g(x)

r(-x)=f(-x)+g(-x)

r(-x)=-f(x)+-g(x)

r(-x)=-(f(x)+g(x))

r(-x)=-(r(x))

r(-x)=-r(x)

So r is odd.

III

s(x)=f(x)\cdot g(x)

s(-x)=f(-x) \cdot g(-x)

s(-x)=-f(x) \cdot -g(x)

s(-x)=f(x) \cdot g(x)

s(-x)=s(x)

So s is even.

So I and II are odd and III is even.

C. is the answer.

8 0
3 years ago
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The circumference of the base of a cone is 24 inches. The slant height of the cone is 20 inches.
loris [4]

The surface area of a cone with circumference base of 24π inches and slant height of 20 inches is 384π inches² in terms of π.

<h3>Surface area of a cone</h3>

surface area = πr(r + l)

where

  • r = radius
  • l = slant height

Therefore,

l = 20 inches

24π = 2πr

r = 12

Therefore,

surface area  = π(12)(12 + 20)

surface area = 12π(12 + 20)

surface area = 12π × 32

surface area = 384π inches²

learn more on surface area here: brainly.com/question/2847956

6 0
2 years ago
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At a college the scores on the chemistry final exam are approximately normally distributed, with a mean of 75 and a standard dev
AysviL [449]

Answer:

b) Chemistry

Step-by-step explanation:

To compare both scored we need to standardize the scores using the following equation:

\frac{x-m}{s}

Where x is the score, m is the mean and s is the standard deviation. So, 82 on chemistry is equivalent to:

\frac{82-75}{15}=0.4667

Because the mean of the scores on the chemistry final exam is equal to 75 and the standard deviation is 15

At the same way, 80 on Calculus is equivalent to:

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Because the mean of the scores on the calculus final exam is equal to 83 and the standard deviation is 13

Now, we can compare the values. So, taking into account that -0.2308 is lower than 0.4667, we can said that the student do better in Chemistry.

5 0
3 years ago
Need answer ASAP! Thanks in advance!
hammer [34]

Answer:

The answer to your question is below

Step-by-step explanation:

Side 1:  3x² - 2x - 1

Side 2: 9x + 2x² - 3

Perimeter: 5x³ + 4x² - x - 3

a) Length of side 1 and side 2

Length = (3x² - 2x - 1) + (9x + 2x² - 3)

            = 3x² - 2x - 1 + 9x + 2x² - 3

            = (3x² + 2x²) + (-2x + 9x) + (-1 - 3)

            = 5x² + 7x - 4

b) Length of the third side

Third side = Perimeter - side 1 - side 2

Third side = 5x³ + 4x² - x - 3 - (5x² + 7x - 4)

Third side = 5x³ + 4x² - x - 3 - 5x² - 7x + 4

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