Divide 80 by 1/5 and then see what percent that answer is of 200
Answer:
C.
Step-by-step explanation:
We are given
are odd which means:


We can tell if a function,
, is even if
.
We can tell if a function,
, is odd if
.
So let's test your I,II,III.
We will be replacing x with -x to find out.
I.





So
is odd.
II






So
is odd.
III





So
is even.
So I and II are odd and III is even.
C. is the answer.
The surface area of a cone with circumference base of 24π inches and slant height of 20 inches is 384π inches² in terms of π.
<h3>Surface area of a cone</h3>
surface area = πr(r + l)
where
- r = radius
- l = slant height
Therefore,
l = 20 inches
24π = 2πr
r = 12
Therefore,
surface area = π(12)(12 + 20)
surface area = 12π(12 + 20)
surface area = 12π × 32
surface area = 384π inches²
learn more on surface area here: brainly.com/question/2847956
Answer:
b) Chemistry
Step-by-step explanation:
To compare both scored we need to standardize the scores using the following equation:

Where x is the score, m is the mean and s is the standard deviation. So, 82 on chemistry is equivalent to:

Because the mean of the scores on the chemistry final exam is equal to 75 and the standard deviation is 15
At the same way, 80 on Calculus is equivalent to:

Because the mean of the scores on the calculus final exam is equal to 83 and the standard deviation is 13
Now, we can compare the values. So, taking into account that -0.2308 is lower than 0.4667, we can said that the student do better in Chemistry.
Answer:
The answer to your question is below
Step-by-step explanation:
Side 1: 3x² - 2x - 1
Side 2: 9x + 2x² - 3
Perimeter: 5x³ + 4x² - x - 3
a) Length of side 1 and side 2
Length = (3x² - 2x - 1) + (9x + 2x² - 3)
= 3x² - 2x - 1 + 9x + 2x² - 3
= (3x² + 2x²) + (-2x + 9x) + (-1 - 3)
= 5x² + 7x - 4
b) Length of the third side
Third side = Perimeter - side 1 - side 2
Third side = 5x³ + 4x² - x - 3 - (5x² + 7x - 4)
Third side = 5x³ + 4x² - x - 3 - 5x² - 7x + 4
Third side = 5x³ + (4x² - 5x²) + (-x - 7x) + (-3 + 4)
Third side = 5x³ - x² - 8x + 1
c) Yes, in this problem we did both operations (addition and subtraction) and we can notice that the polynomials are closed. Also they follow the closure property the addition or subtraction of two polynomials gives another polynomial.