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3 years ago

Find two consecutive positive integers such that the square of the first decreased by 17 equals 4 times the second.

Mathematics

1 answer:

Zina [86]3 years ago

3 0

Answer:

The two consecutive positive integers are 7 and 8

Step-by-step explanation:

Let

x ----> the first positive integer

x+1 ----> the second consecutive positive integer

we know that

$x^{2} -17=4(x+1)$

Solve for x

$x^{2} -17=4x+4\\ \\x^{2}-4x-21=0$

Solve the quadratic equation by graphing

The solution is x=7

see the attached figure

Find the value of x+1

x+1=7+1=8

therefore

The two consecutive positive integers are 7 and 8

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ANSWER:

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STEP-BY-STEP EXPLANATION:

We have the following equation:

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The inverse is the following (we calculate it by replacing f(x) by x and x by f(x)):

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Therefore, the domain is x ≥ -4.

So the correct answer is D.

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