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dangina [55]
3 years ago
14

Find two consecutive positive integers such that the square of the first decreased by 17 equals 4 times the second.

Mathematics
1 answer:
Zina [86]3 years ago
3 0

Answer:

The two consecutive positive integers are 7 and 8

Step-by-step explanation:

Let

x ----> the first positive integer

x+1 ----> the second consecutive positive integer

we know that

x^{2} -17=4(x+1)

Solve for x

x^{2} -17=4x+4\\ \\x^{2}-4x-21=0

Solve the quadratic equation by graphing

The solution is x=7

see the attached figure

Find the value of x+1

x+1=7+1=8

therefore

The two consecutive positive integers are 7 and 8

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By definition, if two lines share the same gradient, they are said to be parallel. So, we know for this equation, it must have a gradient of 1/2.

Now, since the point (-6, 4) passes through the line, we know it must satisfy the equation. Since we have a gradient/slope and a point, we can use the point-gradient form:

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y - 4 = \frac{1}{2}(x + 6)
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Step-by-step explanation:

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