Find two consecutive positive integers such that the square of the first decreased by 17 equals 4 times the second.
1 answer:
Answer:
The two consecutive positive integers are 7 and 8
Step-by-step explanation:
Let
x ----> the first positive integer
x+1 ----> the second consecutive positive integer
we know that
Solve for x
Solve the quadratic equation by graphing
The solution is x=7
see the attached figure
Find the value of x+1
x+1=7+1=8
therefore
The two consecutive positive integers are 7 and 8
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