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IrinaVladis [17]
3 years ago
15

5. List the Amplitude, Horizontal DilatioGraph the parent

Mathematics
1 answer:
dalvyx [7]3 years ago
7 0

2n n2 3n 2x 2n 3n x 3 x 2x 3n 3x

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If a line has a slope of 4 and contains the point (-2,5), what is its equation in slope form?
melomori [17]

Answer:

y-y1=m(x-x1)

y-5=4(x + 5)

y-5=4x+20

5. 5

y = 4x + 25

6 0
3 years ago
PLZ HELP, AND PLZ EXPLAIN
shutvik [7]

Answer:

C

Step-by-step explanation:

To make it easy let's start by organizing our information :

  • AC=12 AND BD=8
  • ABCD is a rhombus
  • K and L are the midpoints of sides AD and CD
  • we notice that the rhombus ABCD is divided into four right triangles

What do you think of when you hear a right triangle ?

  • The pythagorian theorem !

AC and BD  are khown so let's focus on them .

If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?

Simply because they are the diagonals of a rhombus .

ow let's apply the pythagorian theorem :

  • (AC/2)² + (BD/2)² = BC²
  • 6²+4²=52
  • BC²= 52⇒\sqrt{52}=BC

Now we khow that : AB=BC=CD=AD=\sqrt{52}

This isn't enough . Let's try to figure out a way to calculate the length of KL  wich is the base of the triangle

  • KL is parallel to AC
  • k is the midpoint of AD and L of DC

I smell something . yes! Thales theorem

  • KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
  • KL/12=\sqrt{52}/2*\sqrt{52}  
  • KL/12=1/2⇒ KL=6

Now we have the length of the base kl

Now the big boss the height :

  • notice that you khow the length of KL
  • BD crosses kl from its midpoint and DL = \sqrt{52} /2

What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D

  • DL²=(KL/2)²+D²
  • 52/4= 9+ D²
  • D² = 52/4-9 +4 SO D=2

now the height of the trigle is H= BD-D= 8-2=6

NOw the area of the triangle is :

  • A=(KL*H)/2 ⇒ A= (6*6)/2=18

THE ANSWER IS 18 SQ.UN

5 0
3 years ago
How to solve 7*8=_*_+_*_
Volgvan

I'm sorry this is gauge is there anymore info

5 0
3 years ago
. Find the simple interest on a $2,219.00 principal, deposited for 6 years at a
koban [17]

Answer:

SI=PTR/100

SI=2129*6*1.91/100

SI=24398.34/100

SI=243.9834$

7 0
3 years ago
Please help giving BRANLIEST to the best answer THIS SHOULD BE EASY
solniwko [45]

Answer:

the size difference of figure two to figure one gets smaller

Step-by-step explanation:

its kinda obvious

5 0
3 years ago
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