To calculate the frequency of the heterozygote genotype (Pq) for this gene we must use the Hardy-Weinberg equation ( p2 + 2pq + q2 = 1 ). This equation relies on the Hardy-Weinberg principle, a model in population genetics that states that the frequency of the alleles in a population is never changing, only the combinations (the genotypes) are changing.
If there are only two alleles (variations) of this gene in a population, then their frequencies should add up to 1 (100%). From this, we can calculate the frequency of the q allele.
p +q=1
0,3 +q=1
q= 1-0,3
q= 0,7
Now hat we have the frequency of the q allele we can use the HW equation to calculate the frequency of the heterozygotes.
0,09 + 2pq +0.49= 1
2pq +0,58= 1
2pq= 1-0.58
2pq=0,42
The freqency of the heterozygotes in this population is 0.42
Answer: Conduction
Explanation: As the fire starts to heat up the metal hanger it transfers the heat onto your hand.
Conduction Def: The process by which heat or electricity is directly transmitted through a substance
Answer:
The Hardy-Weinberg law states that in a sufficiently large population, in which matings occur randomly and that is not subject to mutation, selection or migration, gene and genotypic free frequencies are kept constant from one generation to another, once a state of equilibrium has been reached, which in autosomal loci is reached after one generation.
It is said that a population is in equilibrium when the alleles of the polymorphic systems maintain their frequency in the population throughout the generations.
Hey there!
I believe the answer you're looking for is radio wave
Hope this helps!
