Question

-2x+4y= 12 3x+7y= 18 last one greatly appreciated

Answer 1

Value of x is $\frac{-6}{13}$ and y is $\frac{36}{13}$

Solution set is ($\frac{-6}{13}$, $\frac{36}{13}$)

Step-by-step explanation:

We need to solve the system of equations given.

$-2x+4y=12\\3x+7y= 18$

Solving

Let:

$-2x+4y=12\,\,eq(1)\\3x+7y=18\,\,eq(2)$

Multiply eq(1) by 3 and eq(2) by 2 and add both

$-6x+12y=36\\6x+14y=36\\-------\\26y=72\\y=\frac{72}{26}\\y=\frac{36}{13}$

Putting value of y in equation 1

$-2x+4y=12\\-2x+4(\frac{36}{13})=12\\-2x+\frac{144}{13}=12\\-2x=12-\frac{144}{13}\\-2x=\frac{12*13-144}{13}\\-2x=\frac{12}{13}\\x=\frac{-6}{13}$

So, value of x is $\frac{-6}{13}$ and y is $\frac{36}{13}$

Solution set is ($\frac{-6}{13}$, $\frac{36}{13}$)

Keywords: System of equations

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