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gayaneshka [121]
3 years ago
5

Tanya’s rotation maps point K(24, –15) to K’(–15, –24). Which describes the rotation?

Mathematics
2 answers:
VARVARA [1.3K]3 years ago
6 0

Answer:

90 degree clockwise rotation.

Hope this helps!

harina [27]3 years ago
4 0
90 degree rotation clockwise : (a,b) --> (b,-a)
so... (24,-15) --> (-15,-24) is a 90 degree clockwise rotation
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Juana compró una camioneta 4x4 a S/ 42 000; además, sabe que la camioneta se depreciará (bajará su precio) en forma lineal duran
prohojiy [21]

Answer:

Una relación lineal es de la forma:

y = a*x + b.

donde a es la pendiente y b es la ordenada al origen.

en este caso, y es el precio de la camioneta, x es el numero de años que pasaron, a es la razon de depreciación de la camioneta y b es el precio inicial de la camioneta, b = $42,000.

Sabemos que después de 5 años, el precio de la camioneta es 21,000, entonces podemos resolver:

$21,000 = a*5 + $42,000

a*5 = $21,000 - $42,000 = -$21,000

a = -$21,000/5 = -$4,200

Esto significa que el precio decae $4,200 por año

4 0
3 years ago
How find derivative of function: y=arcsin(2x+1)<br> ...?
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3 0
3 years ago
Find the value of S for an infinite geometric series with r= 1/6 and a1=10
Lelu [443]
S=a1/1-r=10 x 6/5 = 12
5 0
3 years ago
A circle is centered at the point (-3, 2) and passes through the point (1, 5) what is the radius of the circle
fomenos

Answer:

5 units

Step-by-step explanation:

Center of the circle = (-3, 2)

Point on the circle = (1, 5)

Radius of the circle will be equal to the distance between the points (-3, 2) & (1, 5)

\therefore \: radius \: of \: the \: circle \\  =  \sqrt{ {( - 3 - 1)}^{2} +  {(2 - 5)}^{2}  }  \\  =  \sqrt{ {( - 4)}^{2}  +  {( - 3)}^{2} }  \\  =  \sqrt{16 + 9}  \\  =  \sqrt{25}  \\  \therefore \: radius \: of \: the \: circle  = 5 \: units

6 0
3 years ago
Please help! Will give brainlest!
Vedmedyk [2.9K]

1) 6m = 42

2) 5n - 6 = 4

3) 4n = 200

4) 2v = 50

5) 2 - ( 5/4 ) = 8

6) 48/h = 6

7) n + 10 = 14

8) 5/1 = 2 (1/2)

9) j - 4 = 29

10) 16 + n = 36


3 0
3 years ago
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