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Digiron [165]
3 years ago
13

Mergesort uses the divide-and-conquer technique to sort a list. True False

Computers and Technology
1 answer:
NARA [144]3 years ago
6 0

Answer:

True: Merge Sort sorts a list using divide-conquer approach.

<u>Merge_Sort(B,p,n)</u>  //p is the starting index of array B and n is the last index.

1. if(p<n)

2.        q ← (p+n)/2    //divides the list into two sub-lists

2.        Merge_Sort(B, p, q) //sorts the left half

3.        Merge_Sort(B, q+1, n) //sorts the right half.

4.        Merge(B, p, q, n)

<u>Merge(B, p, q, n)</u>

1.l ← q-p+1.  //no. of elements in left half

2.m ← n-q  //no. of elements in right half.

3.for x ← 1 to l

4.      Left[x] = B[p+x -1] //The elements of left half are copied to Left array

5.for y ← 1 to m.

6.      Right[y]= B[q+y]  //The elements of right half are copied to right array

7. x ← 1, y ←1

8.for z ← p to n.

9.      if( Left[x] ≤ Right[y] ) // to merge the two lists Left and Right, the    //elements are compared.

10.     {   A[z] ← Left[x]   //smaller one comes to the merged list.

11.          x++. }

12.    else

13.      {   A[z] ← Right[y]

14.          y++ }

Explanation:

The Merge_Sort(A, p, n) algorithm first divides the whole array into two halves. Then again divides the sub-lists into it's halves and so on.

Then using merge algorithm it compares the elements of both halves one by one and keep it in sorted order.

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Write a program using integers userNum and x as input, and output userNum divided by x four times. Ex: If the input is: 2000 2
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Answer:

// here is code in c++.

// include header

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

// variables to read input

   int userNum,x;

   cout<<"enter the value of userNum and x :";

   // read the input from user

   cin>>userNum>>x;

   // divide the userNum with x 4 times

   for(int a=0;a<4;a++)

   {

       userNum=userNum/x;

       cout<<userNum<<" ";

   }

       cout<<endl;

return 0;

}

Explanation:

Declare two variables "userNum" and "x". Read the value of these. Run a for loop 4 time and divide the "userNum" with "x" and print  the value of "userNum".

<u>Output:</u>

enter the value of userNum and x :2000 2                                                                                  

1000 500 250 125  

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Answer:

The answer is below

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The second case is in a situation where the value of the attribute of a certain element is not known whether it exists or not.

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Answer:

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Explanation:

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