AP CSA help needed. Java please.

1 answer:

5 0

#include using namespace std;int main(){int year = 12,value = 10,total = 0;do{year++;value *= 2;total += value;}while(value*2 < 1000);cout << "Age: " << year << endl;cout << "Last gift: " << value << endl;cout << "Total: " << total << endl;cin.get();return 0;

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The answer to that is D.

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3 years ago

Design a 16K x 8 memory using the following ICs:

Montano1993 [528]

Answer:

Required memory size is 16k x 8

16k = 24 x 210 = 214

Hence, No. of address lines = 14

No. of data lines = 8

a) Size of IC 1024 x 1

Total number of ICs required = 16k x 8 / 1024 x 1 = 16 x 8 = 128

b) Size of IC 2k x 4

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c) Size of IC 1k x 8

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Explanation:

For a, 10 address lines from A0 to A9 are used to select any one of the memory location out of 1024 memory locations present in a IC.

For b, 11 address lines from A0 to A10 are used to select any one of the memory location out of 2k=2048 memory locations present in a IC.

For c, 10 address lines from A0 to A9 are used to select any one of the memory location out of 1k=1024 memory locations present in a IC.

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