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Sedbober [7]
3 years ago
12

Which of these monitor connector types is the oldest and least desirable to use?

Computers and Technology
2 answers:
UkoKoshka [18]3 years ago
6 0
The correct answer is DVI because it is the oldest according to my research
ella [17]3 years ago
5 0

Answer:

DVI is the oldest out of the four.

Explanation:

DVI and VGA are the oldest, but DVI is oldest and least desirable to use since it is outdated.

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Javascript or java? which one is better?
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SHOW ALL YOUR WORK. REMEMBER THAT PROGRAM SEGMENTS ARE TO BE WRITTEN IN JAVA. Assume that the classes listed in the Java Quick R
Ne4ueva [31]

Answer:

Check the explanation

Explanation:

CODE:-

import java.util.*;

class UserName{

  ArrayList<String> possibleNames;

  UserName(String firstName, String lastName){

      if(this.isValidName(firstName) && this.isValidName(lastName)){

          possibleNames = new ArrayList<String>();

          for(int i=1;i<firstName.length()+1;i++){

              possibleNames.add(lastName+firstName.substring(0,i));

          }  

      }else{

          System.out.println("firstName and lastName must contain letters only.");

      }

  }

  public boolean isUsed(String name, String[] arr){

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          if(name.equals(arr[i]))

              return true;

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      return false;

  }

  public void setAvailableUserNames(String[] usedNames){

      String[] names = new String[this.possibleNames.size()];

      names = this.possibleNames.toArray(names);

      for(int i=0;i<usedNames.length;i++){

          if(isUsed(usedNames[i],names)){

              int index = this.possibleNames.indexOf(usedNames[i]);

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              names = new String[this.possibleNames.size()];

              names = this.possibleNames.toArray(names);

          }

      }

  }

  public boolean isValidName(String str){

      if(str.length()==0) return false;

      for(int i=0;i<str.length();i++){

          if(str.charAt(i)<'a'||str.charAt(i)>'z' && (str.charAt(i)<'A' || str.charAt(i)>'Z'))

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      }

      return true;

  }

  public static void main(String[] args) {

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}

Kindly check the attached image below for the code output.

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3 years ago
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Arada [10]

Answer:

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Explanation:

I hope this helps! Have a good day.

8 0
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