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Alexxx [7]
3 years ago
15

What does a salt bridge do

Chemistry
1 answer:
Tatiana [17]3 years ago
6 0
A salt bridge is a laboratory device used to connect oxidation and reduction have cells of a galvanic cell AKA voltaic cell a type of electrochemical cell. it maintains electrical neutrality within an internal circuit preventing the cell from rapidly running its reaction to equilibrium.
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A student carefully drops a 9.0 g solid Zn pellet initially at 50.0°C into an insulated cup containing 30.0 g of water at 27.8°C
jekas [21]

Answer: choice B

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3 0
3 years ago
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Do you think that participation in a Supervised Agriculture Experience (SAE) prepares a student for a career in the AFN industry
irinina [24]

Answer:

The SAE curriculum includes practical farming tasks conducted outside the scheduled classroom and laboratory period by students. SAEs offer a method for students in agricultural education to gain real-world work opportunities that they are most interested in in the field of agriculture. Supervised agricultural experience is an essential component of agricultural education, and all Agriculture, Food and Natural Resources (AFNR) courses are a necessary component.

Explanation: Hope it helps

6 0
3 years ago
do you agree or not that evidence is only used to back scientific laws and provide evidence why or why not!!!!!! thank you, will
suter [353]

Answer:

yes, because evidence from scientifically research studies, is important because it lets us make decisions based on what works with studies of science we can know if this is right or not  

Explanation:

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4 0
3 years ago
What is released in the process of an atom moving from an excited level to a lower energy level? (2 points) a photon an electron
Tcecarenko [31]

An electron is the correct answer
3 0
3 years ago
What volume of water is required to prepare 0.1 M H3PO4 from 100 ml of 0.5 M solution?
ExtremeBDS [4]

Answer: A volume of 500 mL water is required to prepare 0.1 M H_{3}PO_{4} from 100 ml of 0.5 M solution.

Explanation:

Given: M_{1} = 0.1 M,    V_{1} = ?

M_{2} = 0.5 M,       V_{2} = 100 mL

Formula used to calculate the volume of water is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula as follows.

M_{1}V_{1} = M_{2}V_{2}\\0.1 M \times V_{1} = 0.5 M \times 100 mL\\V_{1} = 500 mL

Thus, we can conclude that a volume of 500 mL water is required to prepare 0.1 M H_{3}PO_{4} from 100 ml of 0.5 M solution.

7 0
3 years ago
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