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salantis [7]
3 years ago
7

Identify each type of bond:

Chemistry
2 answers:
natulia [17]3 years ago
7 0

Answer:

Ionic Bond

Explanation:

In the diagram, the electrons of Sodium are attracted towards the nucleus of Chlorine because of the more +ve charge there

and the nucleus of Sodium is attracted towards the electrons of Chlorine because of the greater -ve charge

But when these 2 atoms come in contact, the electrons of Sodium cannot reach the nucleus of Chlorine due to repulsion from the Chlorine's electrons

Hence, both the atoms come close to each other at the closest distance the repulsion allows

Sindrei [870]3 years ago
3 0

Answer:

ionic bond=72%

covalent character=28%

Explanation:

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Give below are the four mixtures. Choose the correct one which can be separated by winnowing. (i) soybean and chickpeas (ii) whe
victus00 [196]

Answer:

Banana wafers and chips

Explanation:

Winnowing is the process of separating heavier and lighter components of a mixture by blowing air through the mixture. This implies that the relative weight of the particles in the mixture determines whether they can be separated by winnowing or not.

However, chips are heavier than wafers. wafers refer to a very light snack which is easily blown away by a current of air. Hence banana chips and wafers can be separated using the method of winnowing.

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2 years ago
Which is an element? ... air ...carbon dioxide ...hydrogen ...water Description
Natalka [10]
All Elements are obtained in the periodic table & water is Not an element it is a compound.
5 0
2 years ago
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How many atoms of iodine are in 12.75g of CaI2? Hint. How many Iodines are there in one CaI2 particle?
xenn [34]

Answer:

5.225x10^{22}atoms\ I

Explanation:

Hello!

In this case, since 12.75 g of calcium iodide has the following number of moles (molar mass = 293.89 g/mol):

n_{CaI_2}=12.75gCaI_2*\frac{1molCaI_2}{293.89gCaI_2}=0.0434molCaI_2

In such a way, since 1 mole of calcium iodide contains 2 moles of atoms of iodine, and one mole of atoms of iodine contains 6.022x10²³ atoms (Avogadro's number), we compute the resulting atoms as shown below:

atoms\ I=0.0434molCaI_2*\frac{2molI}{1molCaI_2} *\frac{6.022x10^{23}atoms\ I}{1molI} \\\\atoms\ I = 5.225x10^{22}atoms\ I

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4 0
3 years ago
The two elements discovered by Marie Curie are _____ and _____. uranium curium radium polonium
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2 years ago
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Suppose 0.981 g of iron (II) iodide is dissolved in 150. mL of a 35.0 m M aqueous solution of silver nitrate. Calculate the fina
yaroslaw [1]

Answer:

Final molarity of iodide ion C(I-) = 0.0143M

Explanation:

n = (m(FeI(2)))/(M(FeI(2))

Molar mass of FeI(3) = 55.85+(127 x 2) = 309.85g/mol

So n = 0.981/309.85 = 0.0031 mol

V(solution) = 150mL = 0.15L

C(AgNO3) = 35mM = 0.035M = 0.035m/L

n(AgNO3) = C(AgNO3) x V(solution)

= 0.035 x 0.15 = 0.00525 mol

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So, n(FeI(3)) excess = 0.00525 - 0.0031 = 0.00215mol

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8 0
3 years ago
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