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Akimi4 [234]
3 years ago
6

Compare and contrast the burning of wood and the metabolism of glucose in your cells. How are they similar, and how are they dif

ferent?
Chemistry
1 answer:
Alisiya [41]3 years ago
8 0

Burning of wood is a combustion reaction and the metabolism of glucose in your cells is cellular respiratory reaction.

Cellular respiration releases stored energy in glucose molecules and converts it into a form of energy that can be used by cells.

Cellular respiration is the process by which organisms combine oxygen with foodstuff molecules, diverting the chemical energy in these substances into life-sustaining activities and discarding, as waste products, carbon dioxide and water.

Wood as well as many common items that combust are organic (i.e., they are made up of carbon, hydrogen and oxygen). When organic molecules combust the reaction products are carbon dioxide and water (as well as heat)

Similarities:

1. Combustion reaction and metabolism of glucose both require oxygen.

2. Combustion and metabolism of glucose both product carbon dioxide and water

3. Both produces by-products: After cellular respiration and combustion have gotten what they needed from the wood, there will be byproducts from the conversion. In the case of combustion, they are noxious gases like carbon monoxide. In the case of respiration, the sugar molecule is broken into two molecules of pyruvic acid.

4. Catalyst: While breaking apart the bonds to release the stored energy either combustion or sugars for respiration the bonds will not broken by themselves. In each case, a catalyst is required to start the reaction that will break the bonds apart. In the case of combustion, the catalyst is a spark. Wood are flammable, so the spark will ignite the burning, breaking apart the bonds and releasing the energy. For respiration, enzymes are used to break the sugar molecule apart.

Differences

1. Glucose metabolism produces a chemical energy, while combustion produces light and heat energy.

2. Glucose metabolism is an endothermic reaction while combustion is an exothermic reaction (produces heat)

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If parents wanted to pick their child's traits like hair color, gender, eye color, what would doctors have to do?
kap26 [50]

Answer:

Nothing

Explanation:

I would say this because the parents are picking the baby's traits and they make all the decisions. And i guess the doctor would have to follow the traits, if i'm right  i tried

5 0
3 years ago
a balloon filled with a volume of 1.50 L is compressed to a volume of 0.50 L at a constant rate of temperature. if the initial p
Arisa [49]

Answer:

New pressure P2 = 4.95 atm

Explanation:

Given:

Old volume V1 = 1.50 L

New volume V2 = 0.50 L

Old pressure P1 = 1.65 atm

Find:

New pressure P2

Computation:

P1V1 = P2V2

So,

(1.50)(1.65) = (0.50)(P2)

New pressure P2 = 4.95 atm

5 0
3 years ago
When the submarine's density is equal to the density of the surrounding seawater, the submarine will maintain depth. If a 103200
GaryK [48]

Answer:

2.023 m^3 is the total displacement (volume) of the submarine.

Explanation:

Mass of water carried by submarine at 1000 ft depth = m = 2100 kg

The density of seawater at 1000 ft depth = d = 1033 kg/m^3

Volume of the water displaced = V= ?

Total displacement of the submarine = Volume of the water displaced = V

Density=\frac{Mass}{Volume}

V=\frac{m}{d}=\frac{2100 kg}{1033 kg/m^3}=2.023 m^3

2.023 m^3 is the total displacement (volume) of the submarine.

6 0
3 years ago
State the definition of the partial molar Gibbs energy.
balu736 [363]

Explanation :

As we know that the Gibbs free energy is not only function of temperature and pressure but also amount of each substance in the system.

G=G(T,P,n_1,n_2)

where,

n_1\text{ and }n_2 is the amount of component 1 and 2 in the system.

Partial molar Gibbs free energy : The partial derivative of Gibbs free energy with respect to amount of component (i) of a mixture when other variable (T,P,n_j) are kept constant are known as partial molar Gibbs free energy of i^{th} component.

For a substance in a mixture, the chemical potential (\mu) is defined as the partial molar Gibbs free energy.

The expression will be:

\bar{G_i}=\mu_i=\frac{\partial G}{\partial n_i}_{(T,P,n_j)}

where,

T = temperature

P = pressure

n_i\text{ and }n_j is the amount of component 'i' and 'j' in the system.

4 0
3 years ago
On a hot day, you sit on the edge of a pool and dip your feet into the water, causing changes to occur that are related to the p
Pani-rosa [81]
The answer is b and d
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