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Sladkaya [172]
3 years ago
9

One yard of a ribbon costs 3 1/2 dollars. How much should one pay for 5/8 yards?

Mathematics
1 answer:
mash [69]3 years ago
5 0

Multiply the cost per yard by the number of yards bought.

Change 3 1/2 to an improper fraction:

3 1/2 = 7/2

Now you have 7/2 x 5/8

Multiply the top numbers together and then the bottom numbers together:

(7 x 5) / (2 x 8) = 35/16

Now rewrite the improper fraction as a proper fraction:

2 3/16 which would be $2.19

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neonofarm [45]

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Step-by-step explanation: Since x^2 is a exponent, to cancel it out you would have to square root both sides. Therefore, x is equal to +/- 2/3.

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PLEASEEE I DONT KNOW HOW TO DO ITTTT. THE 35.8 IS RIGHT BUT I CANT GET MEASURE OF ANGLE C AND A I GOT 46.2 for A AND 70.8 for C
Rashid [163]

Answer:

Hope it helps....!!!!!

Step-by-step explanation:

AB = c = 38

BC = a = 29

AC = b

Angle ABC = 63 degrees

Solving for AC   "b":

Cosine rule: c^2 = a^2 * b^2 -2ab * cos C

38^2 = 29^2 * b^2 - (2* 29) * b * (cos 38)

1444 = 841 * b^2 - 58 * b * 0.955

(1444 + 58)/0.955 = b^2 * b

1572.77486911 = b^3

11.62935 = b

11.63 = b (rounded to two decimal places)

Now solving for angle A:

Sine rule: a/sinA = b/sinB

29/sinA = 11.63/sin(63)

sinA/29 = sin(63)/11.63

sin A = (sin(63)/11.63) * 29

sin A = 0.41731

A = sin^-1 (0.41731)

A = 24 degrees 39 minutes 53 seconds

Now solving for angle C:

Sine rule: c/sinC = b/sinB

38/sinC = 11.63/sin(63)

sinC/38 = sin(63)/11.63

sin C = (sin(63)/11.63) * 38

sin C = 0.54682

C = sin^-1 (0.54682)

C = 33 degrees 8 minutes 56 seconds

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3 years ago
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If AD=6x+10 and CD=2x+12, find the length of AC
erastovalidia [21]

Answer:

<u>The correct answer is that AC = 4x - 2 or 2(2x - 1)</u>

Step-by-step explanation:

1. Let's review the information given to us for solving the question:

AD = 6x + 10

CD = 2x + 12

2. Let's find the length of AC

AC = AD - CD

Replacing with the real values:

AC = (6x + 10) - (2x + 12)

AC = 6x + 10 - 2x - 12

AC = 6x - 2x + 10 - 12

<u>AC = 4x -2 or 2(2x - 1)</u>

3 0
3 years ago
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