The surface area of the figure is 96 + 64π ⇒ 1st answer
Step-by-step explanation:
* Lats revise how to find the surface area of the cylinder
- The surface area = lateral area + 2 × area of one base
- The lateral area = perimeter of the base × its height
* Lets solve the problem
- The figure is have cylinder
- Its diameter = 8 cm
∴ Its radius = 8 ÷ 2 = 4 cm
- Its height = 12 cm
∵ The perimeter of the semi-circle = πr
∴ The perimeter of the base = 4π cm
∵ The area of semi-circle = 1/2 πr²
∴ The area of the base = 1/2 × π × 4² = 8π cm²
* Now lets find the surface area of the half-cylinder
- SA = lateral area + 2 × area of one base + the rectangular face
∵ LA = perimeter of base × its height
∴ LA = 4π × 12 = 48π cm²
∵ The dimensions of the rectangular face are the diameter and the
height of the cylinder
∴ The area of the rectangular face = 8 × 12 = 96 cm²
∵ The area of the two bases = 2 × 8π = 16π cm²
∴ SA = 48π + 16π + 96 = 64π + 96 cm²
* The surface area of the figure is 96 + 64π
7/8 / 2/5 is equal to 7/8 x 5/2 which equals 35/16, 16 goes into 35 twice so there are 2 wholes there is a remaining of 3 so we put it as a fraction over 16
the answer is 2 3/16
So , the best way I can explain it is to try to find the closest number of lessons for both and add how much it be without going over the budget . I gave an example above
Answer:
Option A for part A and $79 for part B
Step-by-step explanation:
Answer:
The additional information to show ΔABC ≅ ΔDEF by ASA is ≅
Step-by-step explanation:
The given parameters in the figure are;
Angle m∠BAC is congruent to angle m∠FDE
Angle m∠ABC is congruent to angle m∠FED
Therefore, in order to show that ΔABC is congruent to ΔDEF, by the Angle-Side-Angle (ASA) rule of congruency, the additional information is the congruency of the included sides between the given angles as follows;
The additional information to show ΔABC ≅ ΔDEF by ASA is is congruent to which can be written as ≅ .