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Sindrei [870]
3 years ago
6

Construct a control chart for the Lard-O example using 3 sigma limits if samples of size 10 are randomly selected from the proce

ss. The center line is ____. The standard deviation of the sample mean is ____. The UCL
Mathematics
1 answer:
densk [106]3 years ago
8 0

Answer:

The UCL is <u>3.636</u> and the LCL is <u>2.964</u>.

Step-by-step explanation:

The complete question is:

Construct a control chart for the Lard-O example using 3 sigma limits if samples of size 10 are randomly selected from the process. The center line is 3.3. The standard deviation of the sample mean is 0.112. The UCL = ____. The LCL = ____.

Solution:

The control chart is a graphical display used to study how a process changes over time. The data are plotted in time order.  

The parts of a control chart are a central line for the average, an upper line for the upper control limit, and a lower line for the lower control limit.  

These lines are formed using the historical data.

The information provided is:

Center line = <em>m</em> = 3.3

Standard deviation = <em>s</em> = 0.112

Compute the 3σ upper control limit as follows:

\text{UCL}=m+3s

        =3.3+(3\times 0.112)\\=3.636

Compute the 3σ lower control limit as follows:

\text{LCL}=m-3s

        =3.3-(3\times 0.112)\\=2.964

Thus, the UCL is <u>3.636</u> and the LCL is <u>2.964</u>.

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Derrick will need $39,500 in 10 years for college tuition. How much should his parents invest now at 9.5% annual interest, compo
erastova [34]

Answer:

His parents should invest $15,278.16 to reach this goal ⇒ 4th answer

Step-by-step explanation:

* Lets explain how to solve the problem

- Derrick will need $39,500 in 10 years for college tuition

∴ The future amount is $39,500

∴ The time for investment is 10 years

- P is the money his parents invest now at 9.5% annual interest,

 compounded daily

∴ The rate is 9.5% per year compounded daily

- The formula of the compounded interest is:

  A=P(1+\frac{r}{n})^{nt} , where

# A is the future value of money

# P is the value of investment

# r is the rate of interest in decimal

# t is the time of investment

# n is the period of the time

∵ A = $39,500

∵ t = 10

∵ r = 9.5/100 = 0.095

∵ n = 365 ⇒ compounded daily

- Lets use the formula above to find P

∴ 39500=P(1+\frac{0.095}{365})^{365*10}

∴ 39500=p(2.58539)

- Divide both sides by 2.58539

∴ P = $15278.16

∴ His parents should invest $15,278.16 to reach this goal

7 0
3 years ago
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quester [9]

Answer:

\sqrt{2\frac{7}{8} } =\\\sqrt{\frac{25}{8} } =\\\sqrt{\frac{25*2}{16} } =

±5√2/4

5 0
3 years ago
2x - 3y = 13 x + 2y = -4
-Dominant- [34]

Answer:

(2, - 3 )

Step-by-step explanation:

Given the 2 equations

2x - 3y = 13 → (1)

x + 2y = - 4 → (2)

Rearrange (2) expressing x in terms of y by subtracting 2y from both sides

x = - 4 - 2y → (3)

Substitute x = - 4 - 2y into (1)

2(- 4 - 2y) - 3y = 13 ← distribute and simplify left side

- 8 - 4y - 3y = 13

- 8 - 7y = 13 ( add 8 to both sides )

- 7y = 21 ( divide both sides by - 7 )

y = - 3

Substitute y = - 3 into (3) for corresponding value of x

x = - 4 - 2(- 3) = - 4 + 6 = 2

Solution is (2, - 3 )

6 0
3 years ago
How do you find x and y?
alexandr1967 [171]
Y=180-111=69
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That's your answer.
7 0
3 years ago
True or False?
dsp73

Answer:

true

Step-by-step explanation:

 i go to k12 i did this test

6 0
3 years ago
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