Answer:
C
Step-by-step explanation:
Given f(x) then f(x + h) represents a horizontal translation of f(x)
• If h > 0 then a shift to the left of h units
• If h < 0 then a shift to the right of h units
Here the shift is 5 units right, thus g(x) = (x - 5)²
Given f(x) then f(x) + c represents a vertical translation of f(x)
• If c > 0 then a shift up of c units
• If c < 0 then a shift down of c units
Here the shift is 3 units down, thus g(x) = f(x) - 3
Hence
g(x) = (x - 5)² - 3 → C
Answer: Its surface covers 1400 cm²
Explanation:
Since the length of painting = 40 cm
Breadth of painting = 35 cm
Since we know that area of rectangle is product of dimensions.
∴ Area of painting = length × breadth
= 40 cm × 35 cm
= 1400 cm²
∴ Its surface cover 1400 cm².
Given:
To find:
The quadrant of the terminal side of 
and find the value of 
.
Solution:
We know that,
In Quadrant I, all trigonometric ratios are positive.
In Quadrant II: Only sin and cosec are positive.
In Quadrant III: Only tan and cot are positive.
In Quadrant IV: Only cos and sec are positive.
It is given that,
Here cos is positive and sine is negative. So, 
must be lies in Quadrant IV.
We know that,
It is only negative because lies in Quadrant IV. So,
After substituting , we get
Therefore, the correct option is B.
Answer:
x = 50*e∧ -t/100
Step-by-step explanation:
We assume:
1.-That the volume of mixing is always constant 300 gallons
2.-The mixing is instantaneous
Δ(x)t = Amount in - Amount out
Amount = rate * concentration*Δt
Amount in = 3 gallons/ min * 0 = 0
Amount out = 3 gallons/min * x/ 300*Δt
Then
Δ(x)t/Δt = - 3*x/300 Δt⇒0 lim Δ(x)t/Δt = dx/dt
dx/dt = - x/100
dx/ x = - dt/100
A linear first degree differential equation
∫ dx/x = ∫ - dt/100
Ln x = - t/100 + C
initial conditions to determine C
t= 0 x = 50 pounds
Ln (50) = 0/100 * C
C = ln (50)
Then final solution is:
Ln x = - t/100 + Ln(50) or
e∧ Lnx = e ∧ ( -t/100 + Ln(50))
x = e∧ ( -t/100) * e∧Ln(50)
x = e∧ ( -t/100) * 50
x = 50*e∧ -t/100
