What are the perimeter and the area of the square? 80 200 400 8√5 16√5 32√5

There must be 23 students in Ms.Gardner's class because 23 - 30%=6.9 so 7 students are in her class are in the play because if you look at Mr.Logan's class he has 23 students to and there are aslo 7 students in his class are in the play so Mr. Logan's class is basically is holding Ms.Gardner's place

5 0

4 years ago

What's the diameter plz help

Alecsey [184]

18m because the radius is half of the diameter so just double the radius

7 0

3 years ago

A coin is tossed 13 times.

Serga [27]

Answer:

a) 2¹³

b) 0.0873

c) 0.9983

d) 0.9538

Step-by-step explanation:

a) How many different outcomes are possible?

For every toss, there are two possible outcomes (heads or tails), so if we toss the coin 13 times the total of outcomes possible is 2¹³

b) What is the probability of getting exactly 4 heads?

The definition of probability is an event is: number of favourable events/ number of total events.

When we have two possible outcomes p, q and we repeat the experiment multiple times, we apply the Binomial distribution, in this distribution the probability of getting exactly k successes in n trials is given by

$P(X=k) =nCk (p^{k} )(1-p)^{n-k}$ where p represents the probability of success. nCk refers to the combinations of k elements out of n elements.

So we have to know how many different ways we can get exactly 4 heads.

let's name p = probability of getting heads = 0.5

1 -p = probability of getting tails = 0.5

We are going to toss the coin 13 different times and we want to get heads 4 times and tails 9 times.

So, by the Binomial Distribution we would have:

P(X=4) = 13C4 (0.5)⁴(0.5)⁹ = 715 (0.5)¹³ = 0.0873

Thus, the probability of getting exactly 4 heads is 0.0873.

c) What is the probability of getting at least 2 heads?

We are going to use the same binomial distribution but now we need at least to heads, this can be written as 1 - (P(X=0) + P(X=1))

P(X=0) + P(X=1) = 13C0 (0.5)⁰(0.5)¹³ + 13C1 (0.5)¹(0.5)¹² = 0.0001220703125 + 0.0015869140625 = 0.001708984375

1 - 0.001708984375 = 0.998291015625

The probability of getting at least 2 heads is 0.9983

d) What is the probability of getting at most 9 heads?

We are going to use the same binomial distribution but now we need at most 9 heads. This can be written as 1 - (P(X=10) + P(X = 11) + P(X=12) + P(X=13))

1 - (P(X=10) + P(X = 11) + P(X=12) + P(X=13)) =1 -(13C10(0.5)¹⁰(0.5)³ + 13C11(0.5)¹¹(0.5)²+ 13C12(0.5)¹²(0.5)¹ + 13C13(0.5)¹³(0.5)⁰) = 0.95385742188

The probability of getting at most 9 heads is 0.9538

6 0

3 years ago

What are the perimeter and the area of the square? 802004008√516√532√5​

What are the perimeter and the area of the square? 802004008√516√532√5