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zalisa [80]
3 years ago
7

Molly and Lynn set aside money weekly for their savings. Molly already has $ 650 reserved and adds $ 35 each week. Lynn has alre

ady reserved $ 825, but adds only $ 15 each week. Which inequality could you use to determine how many weeks it will take for Molly's savings to exceed Lynn’s savings?
Mathematics
2 answers:
masha68 [24]3 years ago
6 0
The answer is A! I asked the same question and that’s the answer I got.
svetlana [45]3 years ago
5 0
The answer is A my teacher just ask me this
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Solve for x.<br> 1/4+1/2+x= -3/4
o-na [289]

Answer:Negative negative one and 2/3

Step-by-step explanation:First take a4+1/2 that equals three force then 3/4+ X equals -3/4 3/4+ X minus X equals -3/4 minus X 3/4 equals -1 and threeFirst take a4+1/2 that equals three force then 3/4+ X equals -3/4 3/4+ X minus X equals -3/4 minus X 3/4 equals -1 3/4 -1 and 3/4÷3/4 equals -2 aive first take a4+1/2 that equals 3/4 then 3/4+ X equals -3/4 3/4+ X minus X equals -3/4 minus X 3/4 equals -1 3/4 -1 and 3/4÷3/4 equals -2 1/3! I hope this helps!

6 0
3 years ago
The perimeter of the rectangle below is 130 units. Find the value of z
aev [14]

Answer:

9 =z

Step-by-step explanation:

The perimeter of a rectangle is

P = 2(l+w) where l is the length and w is the width

P = 2(3z+2+ 4z)

Combine like terms

P = 2(7z+2)

Substitute in the perimeter

130 = 2( 7z+2)

Divide each side by 2

130/2 = 2/2 ( 7z+2)

65 = 7z+2

Subtract 2 from each side

65-2 = 7z+2-2

63 = 7z

Divide by 7

63/7 = 7z/7

9 =z

8 0
3 years ago
Read 2 more answers
Question 2 -of 15 Step 1 of 1No Time LimitA company manufactures two products. One requires 5 hours of labor, 3 poundsof raw mat
elena-14-01-66 [18.8K]

the cost of labour per hour is $7.20

the cost of raw materials per pound is $11.60

Explanation:

For product one:

time = 5 hours of labour

let the cost labour per hour = x

Amount = 3 pounds of raw amterials

let the cost of one pound raw material = y

Cost to produce each product = $70.8

The equation:

time (cost per hour) + amount (cost of one pound of raw material) = Cost to produce each product

5(x) + 3(y) = 70.80

5x+3y=70.8....\mleft(1\mright)

For product 2:

time = 3.5 hours of labour

let the cost of labour per hour = x

Amount = 13 pounds of raw amterials

let the cost of one pound raw material = y

Cost to produce each product = $176.00

The equation:

time (cost per hour) + amount (cost of one pound of raw material) = Cost to produce each product

3.5(x) + 13(y) = 176

3.5x+13y=176\text{   .... (2)}

combining both equations:

5x + 3y = 70.8 ...(1)

3.5x + 13y = 176 ....(2)

Using elimination method:

To eliminate y, we will multiply equation (1) by 13 and equation (2) by 3 so that both coefficient of y become the same

65x + 39y = 920.4 ...(*1)

10.5x + 39y = 528 ...(2*)

subtract equation (2*) from (1*):

65x - 10.5x + 39y - 39y = 920.4 - 528

54.5x + 0 = 392.4

54.5x = 392.4

divide both sides by 54.5:

x = 392.4/54.5

x = 7.2

substitute for x in any of the equations

Using equation 1: 5x + 3y = 70.8

\begin{gathered} 5\mleft(7.2\mright)+3y=\text{ 70.8} \\ 36\text{ + 3y = 70.8} \\ 3y\text{ = 70.8 - 36} \\ 3y\text{ = 34.8} \\  \\ \text{divide both sides by 3:} \\ \frac{3y}{3}=\frac{34.8}{3} \\ y\text{ = }11.6 \end{gathered}

Hence, the cost of labour per hour is $7.20 and the cost of raw materials per pound is $11.60

6 0
1 year ago
Write each percent as a fraction and as a mixed number or fraction 325% 480% 0.6%
ExtremeBDS [4]

325%=3.25 which is \frac{325}{100} or 3\frac{25}{100} which can be reduced to 3\frac{1}{4}

480%=4.80 which is \frac{480}{100} or 4\frac{80}{100} which can be reduced to 4\frac{4}{5}

0.6%=0.006 which is \frac{3}{500}

I hope this helps.

3 0
3 years ago
Find each percent increase <br>from 20 teachers to 30 teachers ___​
Elanso [62]
20 to 30 is a 10% increase
7 0
3 years ago
Read 2 more answers
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