Answer:
Eve used scale as 2 yards is equal to 1 inch.
Step-by-step explanation:
Given:
Actual Picnic area = 68 yards.
Drawing Picnic area = 34 inches.
We need to find the scale used by Eve.
Solution:
Now we can say that;
scale used by Eve can be calculated by dividing Actual Picnic area from drawing picnic area.
framing in equation form we get;
scale used by Eve = 
Hence Eve used scale as 2 yards is equal to 1 inch.
(a) If <em>f(x)</em> is to be a proper density function, then its integral over the given support must evaulate to 1:

For the integral, substitute <em>u</em> = <em>x</em> ² and d<em>u</em> = 2<em>x</em> d<em>x</em>. Then as <em>x</em> → 0, <em>u</em> → 0; as <em>x</em> → ∞, <em>u</em> → ∞:

which reduces to
<em>c</em> / 2 (0 + 1) = 1 → <em>c</em> = 2
(b) Find the probability P(1 < <em>X </em>< 3) by integrating the density function over [1, 3] (I'll omit the steps because it's the same process as in (a)):

Answer:
a) 4
b) 2
Step-by-step explanation:
a) multiply the coefficients and add the exponents
(4)(1) ·
= 4
b) divide the coefficients and subtract the exponents
(14 ÷ 7) ·
= 2
Answer:
Step-by-step explanation:
17) HI ≅ UH ; GH ≅ TU ; GI ≅ TH
ΔHGI ≅ ΔUTH by Side Side Side congruent
∠G ≅ ∠T ; GI ≅ TH ; ∠GIH ≅ ∠THU
ΔHGI ≅ ΔUTH by Angel Side Angle congruent
19) IJ ≅ KD ; IK ≅ KC ; KJ ≅ CD
ΔIJK ≅ ΔKDC by Side Side Side congruent
∠J ≅ ∠D ; IJ ≅ KD ; ∠I ≅ ∠DKC
ΔIJK ≅ ΔKDC by Angle Side Angle congruent