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Vesnalui [34]
3 years ago
8

Three broad categories of cryptographic algorithms are commonly used to create PRNGs: symmetric block ciphers, asymmetric cipher

s, and hash functions and message authentication codes. T/F
Computers and Technology
1 answer:
RideAnS [48]3 years ago
7 0

Answer:

True.

Explanation:

In generating PRNGs, several specific types of crypto algorithms will be widely will use: linear cipher block, nonlinear ciphers, as well as hash methods and authorization instructions in messages. So, that's why the following scenario is true about the cryptographic algorithms because this is a collection of several excellently defined however complicated mathematics techniques for encoding or decoding information.

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Rewrite this if/else if code segment into a switch statement int num = 0; int a = 10, b = 20, c = 20, d = 30, x = 40; if (num &g
Tanya [424]

Answer:

public class SwitchCase {

   public static void main(String[] args) {

       int num = 0;

       int a = 10, b = 20, c = 20, d = 30, x = 40;

       switch (num){

           case 102: a += 1;

           case 103: a += 1;

           case 104: a += 1;

           case 105: a += 1;

           break;

           case 208: b += 1; x = 8;

           break;

           case 209: c = c * 3;

           case 210: c = c * 3;

           break;

           default: d += 1004;

       }

   }

}

Explanation:

  • Given above is the equivalent code using Switch case in Java
  • The switch case test multiple levels of conditions and can easily replace the uses of several if....elseif.....else statements.
  • When using a switch, each condition is treated as a separate case followed by a full colon and the the statement to execute if the case is true.
  • The default statement handles the final else when all the other coditions are false
3 0
3 years ago
Which terms means device that converts one voltage to another ?
Jet001 [13]

Answer:

I believe it is an adapter

Explanation:

An adapter or adaptor is a device that converts attributes of one electrical device or system to those of an otherwise incompatible device or system. Some modify power or signal attributes, while others merely adapt the physical form of one connector to another.

6 0
3 years ago
Port explorers ​are tools used by both attackers and defenders to identify (or fingerprint) the computers that are active on a
Evgesh-ka [11]

Answer:

b) False.

Explanation:

Port explorers ​are tools used by both attackers and defenders to identify (or fingerprint) the computers that are active on a network, as well as the ports and services active on those computers, the functions and roles the machines are fulfilling, anAn IDPS can be configured to dial a phone number and produce an alphanumeric page or other type of signal or message., is a FALSE statement.

5 0
3 years ago
Samantha has to create a video for her science project on the blossoming of a flower from a bud to one with fully opened petals.
Hitman42 [59]
Samantha would have to use the ‘time-lapse’ technique to film the video in the most efficient way.
5 0
3 years ago
Read 2 more answers
Q1). Write a python program to pass a list to a function and double the odd values and half even values of a list and display li
zepelin [54]

Answer:

\textsf{\large{\underline{Solution}:}}

The given problem is solved using language - Python.

def f(x):

   new_list=[]

   for i in x:

       if i%2==0:

           new_list.append(i//2)

       else:

           new_list.append(i*2)

   return new_list

   

my_list=list(range(1,6))

print('Original List:',my_list)

my_list=f(my_list)

print('Modified List:',my_list)

\textsf{\large{\underline{Logic}:}}

  1. Create a new list.
  2. Iterate over the list passed into the function.
  3. Check if the element is even or not. If true, append half the value of element in the list.
  4. If false, append twice the value of the element in the list.
  5. At last, return the new list.

There is another way of doing this - By using map() function.

—————————————————————————————

def f(x):

   return list(map(lambda x:x//2 if x%2==0 else 2*x,x))

   

my_list=list(range(1,6))

print('Original List:',my_list)

my_list=f(2my_list)

print('Modified List:',my_list)

—————————————————————————————

\textsf{\large{\underline{O{u}tput}:}}

Original List: [1, 2, 3, 4, 5]

Modified List: [2, 1, 6, 2, 10]

8 0
3 years ago
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