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Aloiza [94]
3 years ago
11

Achieving a degree in computer forensics, information technology, or even information systems can provide a strong foundation in

computer forensics. A degree supplemented by a ________ provides greater competencies in the field and makes a candidate even more marketable to a potential employer.
Computers and Technology
1 answer:
guapka [62]3 years ago
6 0

A degree supplemented by a Certifications provides greater competencies in the field and makes a candidate even more marketable to a potential employer.

Explanation:

Computer forensics is field of digital evidences.In a civil or Criminal case computer forensics technology is used to study the digital evidences(like retrieval of deleted files,encrypted files,usage of various disk)

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Each symbol of an octal number corresponds to 3 bits of a binary number. is it true or false​
grin007 [14]

Answer: True.

Explanation: It uses only the 3 bits to represent any digit in binary and easy to convert from octal to binary and then to vice-versa. Hope that helps

5 0
3 years ago
Given public class Fishing { byte b1 = 4; int i1 = 123456; long L1 = (long) i1; //Line A short s2 = (short) i1; //Line B byte b2
Aleksandr [31]

Answer:

Line E.

Explanation:

The  given program is as follows:

public class Fishing {

   byte b1 = 4; int i1 = 123456; long L1 = (long) i1;   //Line A

   short s2 = (short) i1;     //Line B

   byte b2 = (byte) i1;     //Line C

   int i2 = (int)123.456;    //Line D

   byte b3 = b1 + 7;     //Line E

   }

In the above code Line E will not compile and give following compilation error:

error: incompatible types: possible lossy conversion from int to byte

This error is coming because in Java b1 + 7 will be interpreted as int variable expression. Therefore in order to make code of Line E work the expression should be type casted as byte.  

The correct code will be as follows:

public class Fishing {

   byte b1 = 4; int i1 = 123456; long L1 = (long) i1;   //Line A

   short s2 = (short) i1;     //Line B

   byte b2 = (byte) i1;     //Line C

   int i2 = (int)123.456;    //Line D

   byte b3 = (byte)(b1 + 7);     //Line E

   }

5 0
3 years ago
You have to write a program that will read a number followed by a series of bit operations from a file and perform the given ope
tatuchka [14]

The program what will read a number followed by a series of bit operations from file and perform the given operations sequentially on the number is given below.

<h3>What is an operation in computer science?</h3>

An operation, in mathematics and computer programming, is an action that is carried out to accomplish a given task.

There are five basic types of computer operations:

  • Inputting,
  • processing,
  • outputting,
  • storing, and
  • controlling.

<h3>What is the requested program above?</h3>

#include <stdio.h>

#include <fcntl.h>

int main(int argc, char *argv[])

{

  int number, n, v, temp;

  char line[25], fun[10];

  FILE *f = fopen(argv[1], "r");

 

  fgets(line, 24, f);

  sscanf(line, "%d", &number);   //reading the number

  while( fgets(line, 24, f) )

   {

      sscanf(line, "%s %d %d", fun, &n, &v); //reading the commands

      switch(fun[0])           //checking which command to run

      {

          case 'g':    temp = 1;

                      temp = temp<<n;   //shifting for getting that bit

                      printf("%d\n",(number&temp)&&1);

                      break;

          case 's':   temp = 1;

                      temp = temp<<n;   //shifting for setting that bit

                      if(!v)

                      {

                          temp = ~temp;

                          number = number & temp;

                      }

                      else

                      {

                          number = number | temp;

                      }

                      printf("%d\n",number);

                      break;

          case 'c':   temp = 1;

                      temp = temp<<n;   //shifting for complimenting that bit

                      number = number ^ temp;   //xor to complement that bit

                      printf("%d\n",number);

                      break;

          default:printf("not defined");

      }

  }

  return 0;

}

Execution and Output:

terminal-> $ gcc -o first first.c

terminal-> $ ./first file1.txt

1

4

6

Learn more about programs at;
brainly.com/question/16397886
#SPJ1

8 0
2 years ago
What are chemical manufacturers required to provide to anyone who purchases or uses their chemicals for a work purpose? Select a
Julli [10]

Answer:

Labels and Safety Data Sheets.

Explanation:

Label is a short description of what is inside the container. And Safety Data Sheets has everything that is required. You have precautionary measures listed as well as the training details in the safety data sheets. The training PPE is hence not required definitely. However, the only other thing required is the label, as without that you will not come to know what is inside the container from outside. Hence, the above answer.

8 0
3 years ago
Read 2 more answers
Add three methods to the Student class that compare twoStudent objects. One method (__eq__) should test for equality. A second m
shusha [124]

Answer:

class Student(object):

def __init__(self, name, number):

self.name = name

self.scores = []

for count in range(number):

self.scores.append(0)

 

def getName(self):

 

return self.name

 

def setScore(self, i, score):

 

self.scores[i - 1] = score

 

def getScore(self, i):

 

return self.scores[i - 1]

 

def getAverage(self):

 

return sum(self.scores) / len(self._scores)

 

def getHighScore(self):

 

return max(self.scores)

def __eq__(self,student):

return self.name == student.name

 

def __ge__(self,student):

return self.name == student.name or self.name>student.name

 

def __lt__(self,student):

return self.name<student.name

 

def __str__(self):

return "Name: " + self.name + "\nScores: " + \

" ".join(map(str, self.scores))

 

 

def main():

student = Student("Ken", 5)

print(student)

for i in range(1, 6):

student.setScore(i, 100)

print(student)

 

print("\nSecond student")

student2 = Student("Ken", 5)

print(student2)

 

print("\nThird student")

student3 = Student("Amit", 5)

print(student3)

 

print("\nChecking equal student1 and student 2")

print(student.__eq__(student2))

 

print("\nChecking equal student1 and student 3")

print(student.__eq__(student3))

 

print("\nChecking greater than equal student1 and student 3")

print(student.__ge__(student3))

 

print("\nChecking less than student1 and student 3")

print(student.__lt__(student3))

if __name__ == "__main__":

5 0
3 years ago
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