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butalik [34]
3 years ago
12

The symbol located to the left of a code number that identifies a code description that has been revised is _____.

Computers and Technology
1 answer:
Ronch [10]3 years ago
3 0

Answer:

"Triangle" is the right answer.

Explanation:

  • Positioned or installed to something like the left including its compiler, this same code interpretation has indeed been modified throughout the standard requirements of that same CPT.  
  • It designates a characterization of the compiler as well as the written code which has already been rewritten or changed.  

Therefore this statement is correct.

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Write an if/else statement that compares the double variable pH with 7.0 and makes the following assignments to the int variable
levacccp [35]

Answer:

if (pH<7.0){

          neutral=0;

          base=0;

          acid=1;

      }

      else if (pH>7.0){

          neutral=0;

          base=1;

          acid=0;

      }

      else if (pH==7.0){

          neutral=1;

          base=0;

          acid=0;

      }

Explanation:

As required by the question, if and else statements have been used to test the value of the pH and assign the apropriate values to the variables neutral, base and acid.

The code snippet below can be used to prompt the user to enter values for pH

<em>import java.util.Scanner;</em>

<em>public class pHTest {</em>

<em>   public static void main(String[] args) {</em>

<em>      Scanner scr = new Scanner(System.in);</em>

<em>       System.out.println("Enter a value for the pH");</em>

<em>       int neutral, base, acid;</em>

<em>       double pH = scr.nextDouble();</em>

<em> if (pH<7.0){</em>

<em>           neutral=0;</em>

<em>           base=0;</em>

<em>           acid=1;</em>

<em>       }</em>

<em>       else if (pH>7.0){</em>

<em>           neutral=0;</em>

<em>           base=1;</em>

<em>           acid=0;</em>

<em>       }</em>

<em>       else if (pH==7.0){</em>

<em>           neutral=1;</em>

<em>           base=0;</em>

<em>           acid=0;</em>

<em>       }</em>

<em>} }</em>

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4 years ago
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