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Tom [10]
3 years ago
6

Please answer this, 25 points and will give brainliest!!!

Mathematics
1 answer:
Gekata [30.6K]3 years ago
8 0

Answer:

b

Step-by-step explanation:

The median of a triangle is a line that from the vertex touches the middle lets eliminate options

a=ab starts at a vertex but doensn't touch a the middle of a line X

b=cd starts at a vertex and touches the middle of a line Ye

C= ce stars at a vertex but doesn't end at the middle of a line X

d=mb starts in the middle of the triangle and and ends a vertex X

<u>SO THE CORRECT ANSWER IS B</u>

<em>-hope this helps :)</em>

You might be interested in
135pounds 5 months later 120 pounds find percent decrease
Nataly [62]
135 ----- 100%
120 ----- x
------------------------
x = 120*100/135 = 88,8

100-88,8 = 11,2 % 

the decrease percent was 11,2 %

hope helped 
5 0
3 years ago
The sum of a number and its square is 6. Find the numbers
steposvetlana [31]

Answer:

2

Step-by-step explanation:

2+2^2 = 6

5 0
3 years ago
I actually don’t get this and I have a test in 2 days please help what is g(x) and how
nataly862011 [7]

first off, is noteworthy that's the graph of an exponential function, thus the function will be along the lines of g(x) = abˣ , now, what's "a" and "b" values?

well, let's take a peek when x = 0 and x = 1.

\bf g(x) = ab^x \\\\[-0.35em] ~\dotfill\\\\ \begin{cases} x = 0\\ y = 1 \end{cases}\implies 1=ab^0\implies 1=a(1)\implies \boxed{1=a} \\\\[-0.35em] ~\dotfill\\\\ \begin{cases} x = 1\\ y = 4 \end{cases}\implies 4 = ab^1\implies 4=1b^1\implies \boxed{4=b} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill g(x) = 4^x\qquad \qquad \qquad \begin{array}{|c|c|ll} \cline{1-2} x&y\\ \cline{1-2} -2&\frac{1}{4^2}\to \frac{1}{16}\\ -1&\frac{1}{4}\\ 0&1\\ 1&4\\ 2&16\\ \cline{1-2} \end{array}~\hfill

8 0
3 years ago
These cards are put into a bag:
Alenkinab [10]
A. 1/10

B. 2/10

C. 8/10
5 0
3 years ago
Please answer both A. and B.<br><br><br> Thank you!
ioda

Answer: (b)-175 ft

Step-by-step explanation:

In \triangle ABC\ \text{and}\ \triangle CDE

\angle ACB=\angle ECD\quad [\text{vertically opposite angles}]\\\angle ABC=\angle CDE\quad [\text{Each angle is }90^{\circ}]\\\therefore \triangle ABC \sim\ \triangle CDE\quad [\text{by AA similarity criteria}]

(ii)for similar triangles, we can write

\Rightarrow \dfrac{100}{d}=\dfrac{4x}{7x}\\\\\Rightarrow d=100\times \dfrac{7}{4}=175\ ft

5 0
3 years ago
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