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Vitek1552 [10]
3 years ago
7

Help please please help

Mathematics
1 answer:
Vilka [71]3 years ago
4 0

Answer:

(-4,-7)

(-3,-5)

(1,3)

(9,19)

Step-by-step explanation:

2(-4)+1=-8+1=_7

2(-3)+1=-6+1=-5

2(1)+1=2+1=3

2(9)+1=18+1=19

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Suppose that the ages of members in a large billiards league have a known standard deviation of σ = 12 σ=12sigma, equals, 12 yea
asambeis [7]

Answer:

n\geq 23

Step-by-step explanation:

-For a known standard deviation, the sample size for a desired margin of error is calculated using the formula:

n\geq (\frac{z\sigma}{ME})^2

Where:

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  • ME is the desired margin of error.

We substitute our given values to calculate the sample size:

n\geq (\frac{z\sigma}{ME})^2\\\\\geq (\frac{1.96\times 12}{5})^2\\\\\geq 22.13\approx23

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3 0
3 years ago
Monique made several batches of soup for a potluck supper. Each batch required 3\4 0f a pound of potatoes, and she used a total
eimsori [14]

Answer:

The\ value\ of\ \frac{6 \frac{1}{2}}{\frac{3}{4}} \ is\ \frac{26}{3}.

The\ value\ of\ \frac{6 \frac{1}{2}}{\frac{3}{4}} \ is\ 8.67 (Approx).

Step-by-step explanation:

As given

Monique\ made\ several\ batches\ of\ soup\ for\ a\ potluck\ supper.

Each\ batch\ required\ \frac{3}{4}\ of\ a\ pound\ of\ potatoes.

she\ used\ a\ total\ of\ 6 \frac{1}{2}\ pounds\ of\ potatoes.

As given the expression.

= \frac{6 \frac{1}{2}}{\frac{3}{4}}

= \frac{\frac{13}{2}}{\frac{3}{4}}

Solving the above

= \frac{13\times 4}{2\times 3}

= \frac{26}{3}

In the decimal form.

= 8.67 (Approx)

Therefore\ the\ value\ of\ \frac{6 \frac{1}{2}}{\frac{3}{4}} \ is\ \frac{26}{3}.

Therefore\ the\ value\ of\ \frac{6 \frac{1}{2}}{\frac{3}{4}} \ is\ 8.67 (Approx).

6 0
3 years ago
Find the tax amount given the original price and the tax rate. Round to the nearest cent if necessary. Original price: $58.73 Ta
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6.5% of 58.73.
Then minus that amount from 58.73


Mark brainliest please
7 0
2 years ago
Can someone please help with number 32 and 33
labwork [276]
I think you are asking for help because maybe you are nervous to guess....but really just trust your first answer! and think about it!! you are so smart you can do it;) (cuz smart pple ask qs;))
4 0
3 years ago
What is the constant of variation for this relationship?
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