Answer:
Step-by-step explanation:
![=5\displaystyle\int_{0}^{\pi/6}\tan(2x)dx\\=-\frac{5}{2}\ln\cos(2x)|_{0}^{\pi/6}\\=-\frac{5}{2}[\ln\cos(\pi/3) - \ln\cos(0)]\\](https://tex.z-dn.net/?f=%3D5%5Cdisplaystyle%5Cint_%7B0%7D%5E%7B%5Cpi%2F6%7D%5Ctan%282x%29dx%5C%5C%3D-%5Cfrac%7B5%7D%7B2%7D%5Cln%5Ccos%282x%29%7C_%7B0%7D%5E%7B%5Cpi%2F6%7D%5C%5C%3D-%5Cfrac%7B5%7D%7B2%7D%5B%5Cln%5Ccos%28%5Cpi%2F3%29%20-%20%5Cln%5Ccos%280%29%5D%5C%5C)
Answer: Bridge is 21 years old
Step-by-step explanation:
Ok so after reading the question I already know that B (Bridget), A (Angad) and P (Paul) is 49 in the sum of age. I also know that B=A+5 and P=A-4. After that I can assume B=P+5+4. So now after we gather everything, the age of all of them is the same if we delete 5, 4, 4 (From B=P+5+4 and P=A-4). 49-5-4-4=36. So now lets assume they are all 12 (36/3=12). B is 5 years older so lets add 5 to B. B=17, A=12 and P=8. 8+12+17= 37. We now know that but 37 is 12 under 49, so lets add the average 12/3=4 so we add 4 to all of them. B=21 A=16 P=12. 21+16+12=49. So Bridge is 21 years old, Angad is 16 years old and Paul is 12 years old
Answer:
<h3>6 days</h3>
Step-by-step explanation:
Given the inequality expression of the total cost (c) in dollars of renting a car for n days as c ≥ 125 + 50n
To get the maximum number of days for which a car could be rented if the total cost was $425, substitute c = 425 into the expression and find n
425 ≥ 125 + 50n
Subtract 125 from both sides
425 - 125 ≥ 125 + 50n - 125
300≥ 50n
Divide both sides by 50
300/50≥50n/50
6 ≥n
Rearrange
n≤6
<em>Hence the maximum number of days for which a car could be rented if the total cost was $425 is 6days</em>
<em></em>
The answers are in the picture
Have agreat day
Answer:
44
Step-by-step explanation:
-×-=+
11×4=44
so it's equal to =+44
