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aalyn [17]
3 years ago
14

A school held several evening activities last month—a music concert, a basketball game, a drama play, and literacy night. The mu

sic concert was attended by 250 people. How many people came to each of the other activities?
Mathematics
1 answer:
Pie3 years ago
3 0

Complete question :

A school held several evening activities last month—a music concert, a basketball game, a drama play, and literacy night. The music concert was attended by 250 people. How many people came to each of the other activities?

Attendance at a basketball game was 30% of attendance at the concert.

Attendance at the drama play was 140% of attendance at the concert.

Attendance at literacy night was 44% of attendance at the concert.

Answer:

75 ; 350 ; 110

Step-by-step explanation:

Concert attendees = 250

Basketball attendees :

30% of concert attendees

0.3 * 250 = 75 attendees

Drama attendees :

140% * 250

1.4 * 250 = 350 attendees

Literacy night :

44% * 250

0.44 * 250 = 110 attendees

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Which expressions is a Sum?
Pie

Answer:

a

Step-by-step explanation:

sum always means only addition :D mark brainliest if right

3 0
3 years ago
In electrical engineering, the unwanted "noise" in voltage or current signals is often modeled by a Gaussian (i.e., normal) dist
vladimir1956 [14]

Answer:

Cov(X, Y) =0.029.

Step-by-step explanation:

Given that :

The noise in a particular voltage signal has a constant mean of 0.9 V. that is μ = 0.9V ............(1)

Also, the two noise instances sampled τ seconds apart have a bivariate normal distribution with covariance.

0.04e–jτj/10 ............(2)

Having X and Y denoting the noise at times 3 s and 8 s, respectively, the difference of time = 8-3 = 5seconds.

That is, they are 5 seconds apart,

τ = 5 seconds..............(3)

Thus,

Cov(X, Y), for τ = 5seconds = 0.04e-5/10

= 0.04e-0.5 = 0.04/√e

= 0.04/1.6487

= 0.0292

Thus, Cov(X, Y) =0.029.

5 0
3 years ago
The function f(x)f(x) is a quartic function and the zeros of f(x)f(x) are -6−6, -5−5, -2−2 and 11. Assume the leading coefficien
Luden [163]
<h2>Answer: </h2>

\boxed{f(x) = 11x^4 + 22x^3 - 1001x^2 - 5632x - 7260}

<h2>Explanation: </h2>

A quartic function is a function given by the the following equation in standard form:

f(x)=a_{4}x^4+a_{3}x^3+a_{2}x^2+a_{1}x+a_{0} \\ \\ \\ Where: \\ \\ a_{4},a_{3},a_{2},a_{1},a_{0} \ \text{are constant} \\ \\ \text{and} \ a_{4} \ \text{is the leading coefficient}

From the statement we must assume the leading coefficient of f(x) is 11, so:

a_{4}=11

The zeros are:

x=-6 \\ \\ x=-5 \\ \\ x=-2 \\ \\ x=11

So, we can write:

f(x)=11(x-(-6))(x-(-5))(x-(-2))(x-11) \\ \\ \\ So: \\ \\ \mathrm{Rule}:-\left(-a\right)=a \\ \\ \\ Then: \\ \\ f(x)=11\left(x+6\right)\left(x+5\right)\left(x+2\right)\left(x-11\right)

Expand:\left(x+6\right)\left(x+5\right):\ x^2+11x+30: \ \text{Distributive Property} \\ \\ \\ Then: \\ \\ f(x)=11\left(x^2+11x+30\right)\left(x+2\right)\left(x-11\right) \\ \\ \\ Expand:\left(x^2+11x+30\right)\left(x+2\right):\ x^3+13x^2+52x+60:  \ \text{Distributive Property} \\ \\ \\ Then: \\ \\ f(x)=11\left(x^3+13x^2+52x+60\right)\left(x-11\right)

Expand: \left(x^3+13x^2+52x+60\right)\left(x-11\right):\ x^4+2x^3-91x^2-512x-660 \\  (Distributive \ property)

Finally:

f(x) = 11(x^4 + 2x^3 - 91x^2 - 512x - 660) \\ \\ \boxed{f(x) = 11x^4 + 22x^3 - 1001x^2 - 5632x - 7260}

3 0
3 years ago
Which of the following are ordered pairs for the equation y = 1/3x + 1?
Brrunno [24]

answer : (0,1) (3,2) (6,3)

8 0
3 years ago
5 is one-fourth of a number c
Gekata [30.6K]

Answer:

c=20

Step-by-step explanation:

5×4=20, so 5 is 1/4 of c. Hope that this helps you and have a great day :)

8 0
3 years ago
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