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OLEGan [10]
3 years ago
13

Please Help!! What is the next step in the proof? Choose the most logical approach.

Mathematics
1 answer:
marta [7]3 years ago
7 0

Answer:

statement D is correct.

<em>Statement: ∠7 ≅ ∠6 and ∠8 ≅ ∠5</em>

<em>Reason: Vertical Angles Theorem</em>

Step-by-step explanation:

Given that

3 ≅ ∠7 and ∠4 ≅ ∠8

from statement 2 because they are corresponding angles.

∠8 ≅ ∠5

because its vertical angles

The vertical angles theorem is about angles that are opposite each other.

So,

∠4 ≅ ∠8 and ∠8 ≅ ∠5

which means

<h3> ∠4 ≅ ∠5 </h3>

Hence,

∠3 = ∠7

∠4 = ∠5

they are known as interior alternative angles.

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IF P(A)=1/3, P(B)=2/5, and P(AuB)=3/5, what is P(A^B)?
Bumek [7]

The probability of the union of two events is the sum of their probability, minus the probability of their interserction:

P(A \cup B) = P(A) + P(B) - P(A \cap B)

If we plug the known values into this formula, we have

\dfrac{3}{5} = \dfrac{1}{3} + \dfrac{2}{5} - P(A\cap B)

From which we can deduce

P(A\cap B) = \dfrac{1}{3} + \dfrac{2}{5} - \dfrac{3}{5} = \dfrac{2}{15}

So, the probability of A \setminus B is a bit less than P(A), we have to take away all events that belong to B as well:

P(A \setminus B) = P(A) - P(A\cap B) = \dfrac{1}{3} - \dfrac{2}{15} = \dfrac{1}{5}

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3 years ago
A big lockers above a smaller locker they both have 0.5 m wide and 0.6 m deep Big lockers 1.2 m tall and small lockers half of t
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Answer:

0.54\,\,m^3

Step-by-step explanation:

Given: Dimensions of a big locker are 0.5 m × 0.6 m × 1.2 m

Dimensions of a small locker are 0.5 m × 0.6 m × \frac{1.2}{2}=0.6\,\,m (as height of small locker is half the height of big locker )

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Volume of cuboid = length × breadth × height

Total volume of one big locker and one small locker = Total volume of one big locker + total volume of one small locker

= 0.5\times 0.6\times 1.2+0.5\times 0.6\times 0.6

=0.5\times 0.6\left ( 1.2+0.6 \right )\\=0.3(1.8)\\=0.54\,\,m^3

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