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ASHA 777 [7]
3 years ago
8

Determine the domain and range of each graph use inequalities to write your answer​

Mathematics
1 answer:
pav-90 [236]3 years ago
7 0

Answer: Domain is all real numbers. And range is y≥ 3

Step-by-step explanation:

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70+2e+3e=180° answere me ​
Evgen [1.6K]

Answer:

2e+3e=180-70

5e=110

e=110÷5

e=22

8 0
3 years ago
One line is y = 3x + 2 and the other line goes through the point (0, -5). Write equation of line.
Lady_Fox [76]

Answer:

y=3x-4 is the slope-intercept form of the equation of a line.  It is in the form y=mx+b.

    m is the slope (often called "rise over run") and b is the y-intercept (the point where x=0).

The y-intercept is the point (0,-4).

We need one other point.  This is where finding easy calculations pays off.  How about where x=2, y=(3)(2)-4 = 2.

That's the point (2,2).

Step-by-step explanation:

tell me if you get it

3 0
3 years ago
Read 2 more answers
The accounting department analyzes the variance of the weekly unit costs reported by two production departments. A sample of 16
dusya [7]

Answer:

F=\frac{s^2_2}{s^2_1}=\frac{5.5}{2.5}=2.2

Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have n_2 -1 =16-1=15 and for the denominator we have n_1 -1 =16-1=15 and the F statistic have 15 degrees of freedom for the numerator and 15 for the denominator. And the P value is given by:

p_v =2*P(F_{15,15}>2.2)=0.138

For this case the p value is highert than the significance level so we haev enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviations are not significantly different

Step-by-step explanation:

Information given

n_1 = 16 represent the sampe size 1

n_2 =16 represent the sample 2

s^2_1 = 2.5 represent the sample deviation for 1

s^2_2 = 5.5 represent the sample variance for 2

\alpha=0.10 represent the significance level provided

The statistic is given by:

F=\frac{s^2_2}{s^2_1}

Hypothesis to test

We want to test if the variations in terms of the variance are equal, so the system of hypothesis are:

H0: \sigma^2_1 = \sigma^2_2

H1: \sigma^2_1 \neq \sigma^2_2

The statistic is given by:

F=\frac{s^2_2}{s^2_1}=\frac{5.5}{2.5}=2.2

Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have n_2 -1 =16-1=15 and for the denominator we have n_1 -1 =16-1=15 and the F statistic have 15 degrees of freedom for the numerator and 15 for the denominator. And the P value is given by:

p_v =2*P(F_{15,15}>2.2)=0.138

For this case the p value is highert than the significance level so we haev enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviations are not significantly different

5 0
3 years ago
Help please urgent!
myrzilka [38]

Answer:

5

Step-by-step explanation:

8 0
3 years ago
Solve the quadratic equation 4x2 − 121 = 0. Verify your answer using a difference-of-squares factoring method.
Alenkasestr [34]

Answer:

Option d) is correct

That is x equals plus or minus start fraction 11 over two end fraction

Step-by-step explanation:

Given quadratic equation is 4x^2-121=0

To write the given quadratic equation by using a difference-of-squares factoring method:

4x^2-121=0

The above equation can be written as

4x^2-11^2=0

(2x)^2-11^2=0

The above equation is in the form of difference-of-squares

Therefore the given quadratic equation can be written in the form of difference-of-squares

by factoring method is (2x)^2-11^2=0

(2x+11)(2x-11)=0 (which is in the form a^2-b^2=(a+b)(a-b) )

2x+11=0   or   2x-11=0

x=\frac{-11}{2}    or   2x=11

x=\frac{-11}{2}    or   x=\frac{11}{2}

x=\pm \frac{11}{2}

Therefore option d) is correct

That is x equals plus or minus start fraction 11 over two end fraction

5 0
3 years ago
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