Cot^2x - cot^2x cos^2x
= cot^2x - {(cot^2x)(cos^2x)}
= cot^2x { 1 - cos^2x }
= cot^2x { sin^2x }
= (cos^2x/sin^2x) { sin^2x }
= cos^2x
Answer:
x = 8
Step-by-step explanation:
Complimentary angles are angles that add up to 90 degrees. If ABC and DBC are complimentary, then when added together, it equals 90 degrees.
ABC + DBC = 90
6x+13+4x−3 = 90
10x+10 = 90
10x = 80
x = 8
Answer:
40
Step-by-step explanation:
The denominators are 4, 5, and 8.
Write the prime factorizations:
4 = 2²
5 = 5
8 = 2³
To find the least common denominator, multiply the prime numbers with the highest exponents.
2³ × 5 = 40
Sub for each other since both equals y
2x-3=y=2x+5
2x-3=2x+5
minus 2x oth sides
-3=5
false
no solution
(we can see that since slopes are same and y intercepts are differnt, the lines are paralell and therfor never intersect)
D. No solution
Answer:
1.a=2
2. C x=2 and x=-3
Step-by-step explanation:
The standard form for the quadratic function is
ax^2 +bx+c
so we need to rewrite the function to be in this form
2x^2 -10 = 7x
Subtract 7x from each side
2x^2 -7x-10 = 7x-7x
2x^2 -7x-10 = 0
a =2, b= -7 c=-10
2. The quadratic formula is
-b ± sqrt(b^2 -4ac)
----------------------------
2a
2x^2 + 2x=12
Lest get the equation in proper form
2x^2 + 2x-12 = 12-12
2x^2 +2x-12 =0
a=2 b=2 c=-12
Lets substitute what we know
-2 ± sqrt(2^2 -4(2)(-12))
----------------------------
2(2)
-2 ± sqrt(4+96)
----------------------------
2(2)
-2 ± sqrt(100)
----------------------------
4
-2 ± 10
----------------------------
4
-2 + 10 -2-10
----------- and --------------
4 4
8/4 and -12/4
2 and -3
