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Eddi Din [679]
3 years ago
15

The solution of two linear equations is (-2,2). One equations has a slope of 3. The slope of the other equation is the negative

reciprocal of the slope of the first.
The system described above is represented by the following equations.

Mathematics
2 answers:
sineoko [7]3 years ago
5 0

Answer:

Its true ⇒ answer (a)

Step-by-step explanation:

* The solution of two linear equation means that this solution

  is a solution for each equation

* To check if the point is a solution of an equation

- Substitute its coordinates in the equation, if the left hand side

 is equal the right hand side, then the point is a solution

 of this equation

* Lets study our problem

- (-2 2) is the solution of two linear equations

- The slope of one equation is 3

- The slope of the second equation is the negative reciprocal

 of the slope of the first, means = -1/3

* Check the this conditions in the given equations

- In the equation y = 3x + 8 ⇒ the slope = 3

- In the equation y = -1/3 x + 4/3 ⇒ the slope = -1/3

* Now lets substitute the solution (-2 , 2) in the both equations

- First equation

∵ y = 2 ⇒ L.H.S

∵ 3(-2) + 8 = 2 ⇒ R.H.S

∵ L.H.S = R.H.S

∴ (-2 , 2) is a solution of the equation y = 3x + 8

- Second equation

∵ y = 2 ⇒ L.H.S

∵ (-1/3)(-2) + 4/3 = 2/3 + 4/3 = 6/3 = 2 ⇒ R.H.S

∵ L.H.S = R.H.S

∴ (-2 , 2) is a solution of the equation y = -1/3 x + 4/3

∴ (-2 , 2) is the solution of the two equations

* Its true

Irina-Kira [14]3 years ago
4 0

Answer:

true

Step-by-step explanation:

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let sin(θ) =3/5 and tan(y) =12/5 both angels comes from 2 different right trianglesa)find the third side of the two tringles b)
statuscvo [17]

In a right triangle, we haev some trigonometric relationships between the sides and angles. Given an angle, the ratio between the opposite side to the angle by the hypotenuse is the sine of this angle, therefore, the following statement

\sin (\theta)=\frac{3}{5}

Describes the following triangle

To find the missing length x, we could use the Pythagorean Theorem. The sum of the squares of the legs is equal to the square of the hypotenuse. From this, we have the following equation

x^2+3^2=5^2

Solving for x, we have

\begin{gathered} x^2+3^2=5^2 \\ x^2+9=25 \\ x^2=25-9 \\ x^2=16 \\ x=\sqrt[]{16} \\ x=4 \end{gathered}

The missing length of the first triangle is equal to 4.

For the other triangle, instead of a sine we have a tangent relation. Given an angle in a right triangle, its tanget is equal to the ratio between the opposite side and adjacent side.The following expression

\tan (y)=\frac{12}{5}

Describes the following triangle

Using the Pythagorean Theorem again, we have

5^2+12^2=h^2

Solving for h, we have

\begin{gathered} 5^2+12^2=h^2 \\ 25+144=h^2 \\ 169=h^2 \\ h=\sqrt[]{169} \\ h=13 \end{gathered}

The missing side measure is equal to 13.

Now that we have all sides of both triangles, we can construct any trigonometric relation for those angles.

The sine is the ratio between the opposite side and the hypotenuse, and the cosine is the ratio between the adjacent side and the hypotenuse, therefore, we have the following relations for our angles

\begin{gathered} \sin (\theta)=\frac{3}{5} \\ \cos (\theta)=\frac{4}{5} \\ \sin (y)=\frac{12}{13} \\ \cos (y)=\frac{5}{13} \end{gathered}

To calculate the sine and cosine of the sum

\begin{gathered} \sin (\theta+y) \\ \cos (\theta+y) \end{gathered}

We can use the following identities

\begin{gathered} \sin (A+B)=\sin A\cos B+\cos A\sin B \\ \cos (A+B)=\cos A\cos B-\sin A\sin B \end{gathered}

Using those identities in our problem, we're going to have

\begin{gathered} \sin (\theta+y)=\sin \theta\cos y+\cos \theta\sin y=\frac{3}{5}\cdot\frac{5}{13}+\frac{4}{5}\cdot\frac{12}{13}=\frac{63}{65} \\ \cos (\theta+y)=\cos \theta\cos y-\sin \theta\sin y=\frac{4}{5}\cdot\frac{5}{13}-\frac{3}{5}\cdot\frac{12}{13}=-\frac{16}{65} \end{gathered}

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kykrilka [37]

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3 years ago
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Arte-miy333 [17]

Answer:

-7/2y

Step-by-step explanation:

cancel out the Z's than youre left with -7/2y :}

8 0
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Captain Salamander has a lazy time on the trip and spends about 15 hours a day sleeping. What fraction of the day does he spend
padilas [110]

Well there is 24 hours in a day so 24 - 15 = 9. So he spends 9 hours awake.

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3 years ago
To get from the post office to the library, Sindy walked due north and then due east. The distance Sindy walked east is 20 meter
kaheart [24]
A. x∧2+(x+20∧2=150∧2  is correct.

because you need to plug the numbers into the pathagoreum theorum which is 
a∧2+b∧2=c∧2

150 is our c because it is the side right accross from the right angle.

which number is a and which number is b does not matter.

x is the distance north so we can assign that to a and the distace east is north plus 20 so we can assign b to x+20.
6 0
3 years ago
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