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Sergio039 [100]
3 years ago
5

Convert 4 ⅓ to an improper fraction.

Mathematics
2 answers:
morpeh [17]3 years ago
5 0

Answer:

13/3

Step-by-step explanation:

evablogger [386]3 years ago
3 0

Answer: 13/3

Step-by-step explanation:

1. multiply The Whole number by the denominator.

4x 3 = 12

2. Add the product to the numerator

1+12=13

The denominator stays the same.

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The length of a rectangle is 18 cm and its breadth is 11 cm. Find area of the rectangle.
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Step-by-step explanation:

Area = length×breath

=18×11

=198cm²

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Which sequence could be partially defined by the recursive formula f (n + 1) = f(n) + 2.5 for n ≥ 1?
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<span>–10, –7.5, –5, –2.5, …

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Which operation should you perform first when you simplify 63-(2+54x6) / 5
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Multiply 54 and 6

Step-by-step explanation:

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If the null space of A4×5 is exactly a two-dimensional plane, answer the following:
Hatshy [7]

Answer:

I.

A is a 4 x 5 matrix => A: U -> V, dim U = 5, dim V = 4

Null space is exactly two dimensional plane

dim null (A) = 2

II.

Rank A = dim U - dim Null A = 5 - 2 = 3

III.

Number of linearly Independent columns of A is the rank of A = 3

IV.

Yes, The system Ax = b has no solution sometimes as range of A \neq V

V.

Yes,Sometimes Ax = b has a unique solution

VI.

Yes, sometimes Ax = b has infinitely many solutions

8 0
3 years ago
The doubling period of a bacterial population is 15 minutes. At time t= 80 minutes, the bacterial population was 90000​
Papessa [141]

Answer:

here i finished!

hope it helps yw!

Step-by-step explanation:

The doubling period of a bacterial population is 15 minutes.

At time t = 90 minutes, the bacterial population was 50000.

Round your answers to at least 1 decimal place.

:

We can use the formula:

A = Ao*2^(t/d); where:

A = amt after t time

Ao = initial amt (t=0)

t = time period in question

d = doubling time of substance

In our problem

d = 15 min

t = 90 min

A = 50000

What was the initial population at time t = 0

Ao * 2^(90/15) = 50000

Ao * 2^6 = 50000

We know 2^6 = 64

64(Ao) = 50000

Ao = 50000/64

Ao = 781.25 is the initial population

:

Find the size of the bacterial population after 4 hours

Change 4 hr to 240 min

A = 781.25 * 2^(240/15

A = 781.25 * 2^16

A= 781.25 * 65536

A = 51,199,218.75 after 4 hrs

6 0
3 years ago
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