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Fudgin [204]
3 years ago
11

If a sample of an unknown material with a mass of 0.68 g and a volume of 0.8 cm3 is dropped

Physics
1 answer:
Anna71 [15]3 years ago
4 0
As the density of the unknown substance is 0.68g/0.8ml = 0.85g/ml, it is less dense than the maple syrup at 1.33g/ml and will float.
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Pls help me to answer this​
kifflom [539]

Answers:

  1. Geography (geo-gra-phy)
  2. Location (lo-ca-tion)
  3. Coordinates (co-or-di-nates)
  4. Landmass (land-mass)
  5. Absolute (ab-so-lute)
  6. Vicinal (vi-ci-nal)
  7. Insular (in-su-lar)
  8. Relative (re-la-tive)

Note: It's very likely the tile labeled "MAL" should be "NAL", and that "MATES" should be "NATES".

==================================

Explanations:

  1. Geography deals with not only places, but also the people and cultures in those places. That's more of a social or human geography course. Natural geography talks about land formations, volcanos, rivers, etc.
  2. I'm not sure there's much to say about this term. It's simply a position in 2D or 3D space depending on context.
  3. Coordinates are things like longitude and latitude. Think of the (x,y) points on a grid. Side note: The tile "mates" should be labeled as "nates". Your teacher made a typo. In some dialects, the "co" and "or" are pronounced together; almost sounding like "core".
  4. The term "landmass" is exactly what you'd expect it should be: a big chunk of land.
  5. When you mention if a person has absolute freedom, then we consider that person having no restrictions of movement/choice/etc. It also refers to something like a local coordinate space talks about the surrounding area, whereas an absolute coordinate space doesn't have to worry about such issues. Eg: a local coordinate could be "go 5 blocks from the store" and an absolute coordinate would be to provide a GPS location. As you can see, the local coordinate space needs the store as an anchor or else it wouldn't make much sense.
  6. To be quite honest, I had a bit of a long time to find this answer. I suppose if you are good with words then it shouldn't be too much of a struggle. But I did a reverse dictionary lookup and only focused on three syllable words until I arrived at "vicinal" which is related to "vicinity". Eg: The person was just in the vicinity. Anyways, I haven't really seen this word used too much in everyday language, so that's probably why it took a while for me. I have a feeling your teacher meant to write "NAL" instead of "MAL" as one of the tiles. This appears to be the second time s/he mixed up M's with N's (the first time being "MATES" mixed up with "NATES"; see problem 3).
  7. Insular is an adjective referring to a person or group of people cut off from the larger world. Think of a small town where it's hard to reach. Islands are of course like this, but we could have an "island" rural small town or some culture in a remote location that is on a continent somewhere. It doesn't necessarily have to be a literal island surrounded by water. Think of the word "insulate" to help remember "insular". Also, the term "insular" could refer to the deliberate attempt to keep oneself (or one group) closed off from the rest of the world. An example of this is the Amish culture being insular to the American culture surrounding them.
  8. If object A is larger than object B, then we say A is relatively large  compared to B. This is one example usage of the word "relative".
4 0
2 years ago
After turning on the power source connected to your two electrodes, we expect to see the microbeads moving through the solution.
Rudik [331]

Answer:

the pearls have an electrical charge induced by contact with the ions of the solution and these charges are attracted by the electrode by a force electric

Explanation:

The pearls are suspended in a solution, when connecting the power source, it is subjected to an electric shock, the pearls have an electrical charge induced by contact with the ions of the solution and these charges are attracted by the electrode by a force electric

            F = q E

4 0
3 years ago
A leaky 10-kg bucket is lifted from the ground to a height of 10 m at a constant speed with a rope that weighs 0.9 kg/m. Initial
sladkih [1.3K]

Answer:

The work done shall be 14715 Joules

Explanation:

The work done by a force 'F' in a displacement 'dy' is given by

W=m(y)g\times dy

At any position 'y' the weight shall be sum of weft of water and weight of string

\therefore m(y)=m_{water}(y)+m_{string}(y)\\\\m(y)=30(1-\frac{y}{10})+0.9y

Thus applying values we get

W=\int m(y)g\times dy\\\\W=\int_{0}^{10}(30(1-\frac{y}{10}+0.9y)\times g)dy\\\\Solving\\W=294.3\int_{0}^{10}(1-\frac{y}{10}+0.9y)dy\\\\W=14715J

8 0
3 years ago
Two electrons travel towards each other at 0.2 c parallel to the laboratory x-axis. What is the relative velocity of one electro
Leya [2.2K]

1) In the reference frame of one electron: 0.38c

To find the relative velocity of one electron with respect to the other, we must use the following formula:

u'=\frac{u-v}{1-\frac{uv}{c^2}}

where

u is the velocity of one electron

v is the velocity of the second electron

c is the speed of light

In this problem:

u = 0.2c

v = -0.2c (since the second electron is moving towards the first one, so in the opposite direction)

Substituting, we find:

u'=\frac{0.2c+0.2c}{1+\frac{(0.2c)(0.2c)}{c^2}}=\frac{0.4c}{1+0.04}=0.38c

2) In the reference frame of the laboratory: -0.2c and +0.2c

In this case, there is no calculation to be done. In fact, we are already given the speed of the two electrons; we are also told that they travel in opposite direction, so their velocities are

+0.2c

-0.2c

5 0
3 years ago
The length of a cylindrical axon is 8 cm and its radius of 8μm,and the thickness of the membrane is 0.01μm,dielectric constant (
GuDViN [60]

Answer:

9.965 nF

Explanation:

The capacitance of the axon C = εA/d where ε = dielectric constant = 24.78 × 10⁻¹² F/m, A = surface area of axon = 2πrL where r = radius of axon = 8 μm = 8 × 10⁻⁶ m and L = length of axon = 8 cm = 8 × 10⁻² m and d = thickness of membrane = 0.01 μm = 0.01 × 10⁻⁶ m

So, C = εA/d

C = ε2πrL/d

Substituting the of the values variables into the equation, we have

C = ε2πrL/d

C =  24.78 × 10⁻¹² F/m × 2π × 8 × 10⁻⁶ m × 8 × 10⁻² m/0.01 × 10⁻⁶ m

C =  9964.63 × 10⁻²⁰ Fm/0.01 × 10⁻⁶ m

C =  996463 × 10⁻¹⁴ F

C = 9.96463 × 10⁻⁹ F

C = 9.96463 nF

C ≅ 9.965 nF

6 0
3 years ago
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