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3 years ago

7

A golf ball is whacked in a direction 25 degrees south of the east axis. The ball travels 125m. What are the east and north comp

onents of its displacement?

1 answer:

Natalka [10]3 years ago

3 0

<u>We are given:</u>

Direction of motion: 25 degrees south of the east axis

Distance covered = 125 m

<u>East component of the Ball:</u>

<em>this component is denoted by green color in the image</em>

Once we drop a perpendicular from the end of the direction vector on the x-axis, we get a right angled triangle

The magnitude of the side of the triangle on the x-axis denotes the east component of the ball

Using trigonometry, we find that the east component of the ball is:

125 * Cos(25 degrees)

125 * 0.9 = 112.5 i (here, i denotes rightward direction on the x-axis)

<u />

<u>North Component of the Ball:</u>

<em>this component is denoted by blue color in the image</em>

Using trigonometry, we find that the North component of the ball is:

125* Sin(25 degrees) (-j) <em>[j denotes upward movement on the y-axis, since the vector is acting downwards, we have used '-j']</em>

125 * 0.42 (-j)

52.5 (-j) = -52.5 j

Therefore the direction vector of the ball is 112.5 i - 52.5 j

<em>where 112.5 i is the East Component and -52.5 is the North Component</em>

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