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2 years ago

I’ll give Brainliest I need help please & thanks

Mathematics

2 answers:

Feliz [49]2 years ago

8 0

I’m cffffffdddddeddddrrddrrr

gizmo_the_mogwai [7]2 years ago

8 0

46, 67
..—————————————————————

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I need to find x. It wants me to find the indicated angle measure.

Nataliya [291]

Answer:

x=27

Step-by-step explanation:

(2x-18)+(4x)=180 bc its a straight line

simplify

6x-18=180

-18 -18

6x=162

divide

x=27

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2 years ago

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Can you guys help me

Akimi4 [234]

Answer:

Step-by-step explanation:

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3 years ago

Franco made a dozen muffins for his party. Upon taking them out of the oven,

Naddik [55]

Answer:

Option B.

Step-by-step explanation:

This question is incomplete; find the complete question with the attachment.

Franco made number of muffins = a dozen

A dozen muffins = 12 muffins

Number of muffins were burned = 2

Remaining muffins = 12 - 2 = 10

Franco served 7 of the remaining non-burned muffins,

Fraction of muffins served = $\frac{7}{10}$

Remaining muffins = 3

Fraction of remaining muffins = $\frac{3}{10}$

Fraction of remaining non-burned muffins we can get from,

$\frac{10}{10}-\frac{7}{10}=\frac{3}{10}$

Option B is the correct equation.

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3 years ago

A bicycle lock has a four-digit code. The possible digits, 0 What is the probability that the lock code will begin with

nika2105 [10]

Answer:

0.1-0.6

Step-by-step explanation:

First let's find the number of the elements in the sample space, that is the total number of codes that can be produced.

The first digit is any of {0, 1, 2...,9}, that is 10 possibilities

the second digit is any of the remaining 9, after having picked one.

and so on...

so in total there are 10*9*8*7 = 5040 codes.

a. What is the probability that the lock code will begin with 5?

Lets fix the first number as 5. Then there are 9 possibilities for the second digit, 8 for the third on and 7 for the last digit.

Thus, there are 1*9*8*7=504 codes which start with 5.

P(first digit is five)=

b. What is the probability that the lock code will not contain the number 0?

from the set {0, 1, 2...., } we exclude 0, and we are left with {1, 2, ...9}

from which we can form in total 9*8*7*6 codes which do not contain 0.

P(codes without 0)=n(codes without 0)/n(all codes)=(9*8*7*6)/(10*9*8*7)=6/10=0.6

Answer:

0.1 ; 0.6

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Write -0.37 as a quotient of integers to show that is rational.

Gnoma [55]

Answer:

Step-by-step explanation:

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