1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
EastWind [94]
3 years ago
12

What factors does 2 have?

Mathematics
1 answer:
Vanyuwa [196]3 years ago
4 0

Answer:

2 and 1

Step-by-step explanation:

2 only has the factors 2 and 1 because it is a prime number.

You might be interested in
Can someone please give me a scenario of this please Y=3x + 2
Deffense [45]

Ahhh I think that is cheating?

Soz I know the anaswer but I cant tell you have to do by your self to learn you can't always ask for answers :<

7 0
3 years ago
Read 2 more answers
Four ninths plus five sixths
sergey [27]

Answer:

1 5/18

one and five eighteenths  

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
I need help with no.7
ziro4ka [17]

Answer:

  (a) 315°

  (b) 3°

  (c) 238°

Step-by-step explanation:

Bearings are measured clockwise from north. The triangle described is illustrated in the attachment.

<h3>(a)</h3>

The bearing of P from R is 180° different from the bearing of R from P it will be ...

  135° +180° = 315° . . . . bearing of P from R

__

<h3>(b)</h3>

The bearing of Q from R is 48° more than the bearing of P from R, so is ...

  315° +48° = 363°, or 3° . . . . bearing of Q from R

__

<h3>(c)</h3>

The angle QPR has a value that makes the sum of angles in the triangle equal to 180°. It is ...

  180° -48° -55° = 77°

The bearing of Q from P is 77° less than the bearing of R from P, so is ...

  135° -77° = 58°

As above, the reverse bearing from Q to P is ...

  58° +180° = 238° . . . . bearing of P from Q

8 0
3 years ago
What is the domain of the function y = 2 StartRoot x minus 5 EndRoot?
Juli2301 [7.4K]

Answer:

The domain of the function should be:

'x greater than or equal to negative -5'.

Hence, option A is true.

Step-by-step explanation:

Given the expression

2\sqrt{x-5}

The domain of a function is the set of input or arguments for which the function is real and defined

We know that the value, inside the radicand, is the number found inside a radical symbol which must be greater than 0, otherwise, it would make the function undefined,

i.e.

x-5 ≥ 0

x ≥ 5

In other words, the domain of the function should be:

'x greater than or equal to negative -5'.

Therefore, the domain of the function:

x ≥ 5

\mathrm{Domain\:of\:}\:2\sqrt{x-5}\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\ge \:5\:\\ \:\mathrm{Interval\:Notation:}&\:[5,\:\infty \:)\end{bmatrix}

Hence, option A is true.

3 0
3 years ago
Read 2 more answers
Maddy bought 2 ⅔ pounds of grapes and 1 ⅕ pounds of apples. If she bought bananas that weighed 1 ¼ times as much as the grapes,
spin [16.1K]

Answer:

3 whole number, 1/3

Step-by-step explanation:

To solve this, Multiply the value of the banana to the weight of the Grapes.

Please find the attached file for a comprehensive Solution.

Maths is fun !

4 0
3 years ago
Other questions:
  • Which expression is equal to 20 - (8 + 5) + 4?
    11·1 answer
  • the line graph shows Calvin's saving account balance at the end of each month for 6 months. about how much more money did Calvin
    13·1 answer
  • there are 16 boys and 24 girls in chorus whats the percent of the total number of students in chorus are boys?
    5·2 answers
  • ANSWER ASAP!!
    5·1 answer
  • How to add fractions containing pi
    8·1 answer
  • Ellen purchased a dishwasher, which cost $315 before the 9.22% sales tax. She used the machine an average of 10 times per week f
    7·2 answers
  • A game room has a floor that is 225 feet by 40 feet. A scale drawing of the floor on grid paper uses a scale of 2 units:5 feet.
    11·1 answer
  • Can you please help me
    15·1 answer
  • -15
    14·1 answer
  • Solve for r. r/5 = -9
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!