I think this is the answer to your question And also the solution
I need help with no.7
1 answer:
Answer:
(a) 315°
(b) 3°
(c) 238°
Step-by-step explanation:
Bearings are measured clockwise from north. The triangle described is illustrated in the attachment.
<h3>(a)</h3>The bearing of P from R is 180° different from the bearing of R from P it will be ...
135° +180° = 315° . . . . bearing of P from R
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<h3>(b)</h3>The bearing of Q from R is 48° more than the bearing of P from R, so is ...
315° +48° = 363°, or 3° . . . . bearing of Q from R
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<h3>(c)</h3>The angle QPR has a value that makes the sum of angles in the triangle equal to 180°. It is ...
180° -48° -55° = 77°
The bearing of Q from P is 77° less than the bearing of R from P, so is ...
135° -77° = 58°
As above, the reverse bearing from Q to P is ...
58° +180° = 238° . . . . bearing of P from Q
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Answer:
See the attached image for solutions.
Step-by-step explanation:
X-ray vision to all students ratio:
<u>6:36</u>, which can be simplified to <u>1:6</u>.
<u />
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<u>8:36</u>, which can be simplified to <u>2:9</u>.
Flight to inivisibility ratio:
<u>8:36</u>, which can be simplified to <u>2:3</u>.
Hope this helps! :)
