The first term, a, is 2. The common ratio, r, is 4. Thus,
a_(n+1) = 2(4)^(n).
Check: What's the first term? Let n=1. Then we get 2(4)^1, or 8. Is that correct? No.
Try this instead:
a_(n) = a_0*4^(n-1). Is this correct? Seeking the first term (n=1), does this formula produce 2? 2*4^0 = 2*1 = 2. YES.
The desired explicit formula is a_(n) = a_0*4^(n-1), where n begins at 1.
Answer:
3120
Step-by-step explanation:
step 1:multiply 8 with 0 and 7 with 0
step 2:add a 0 in the end and multiply 8 with 4 . you get 32. take 2 and carry over 3. multiply 7 with 4. you get 28 . add 3 you get 31. now add. you get 3120
Answer:
1) y > x
2) x > 5 > y
3) x ≤ 4 ( or 4 ≥ x )
4) x = y
Step-by-step explanation:
1) 1. y is greater than x
2. so y > x
2) 1. 5 is less than x and more than y
2. we can write this like x > 5 > y
3. you can just squish them together as a shortcut usually: x > 5 and 5 > y --> x > 5 > y
3) 1. x is for at most, we can say this as x is less than or equal to 4
2. this is written as x ≤ 4 or 4 ≥ x
4) 1. x - y = 0 so x and y must be the same value
2. therefore x = y
Answer: the height is 11.2
Step-by-step explanation:
The answer would be 48. I hope that helped
