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Fantom [35]
3 years ago
13

An angle bisector of a triangle divides the opposite side of the triangle into segments 6 cm and 4 cm long. A second side of the

triangle is 7.4 cm long. Find the longest and shortest possible lengths of the third side of the triangle. Round answers to the nearest tenth of a centimeter. A. 44.4 cm, 11.1 cm B. 44.4 cm, 3.2 cm C. 11.1 cm, 4.9 cm D. 24 cm, 4.9 cm
Mathematics
1 answer:
Usimov [2.4K]3 years ago
5 0
It will probably be A Hopes This Helps.
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iragen [17]

Step-by-step explanation:

Slope of the line: 6/5.

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In a fruit cocktail, for every 20 ml of orange juice you need 10 ml of apple juice and 15 ml of coconut milk. What proportion of
tresset_1 [31]
Since you have to mix all of it together, the whole cocktail is 20+10+15=45.
And the portion that is coconut milk is 15ml. So that means there is 15 out of 45 or 15/45 coconut milk in the cocktail. Then the simpelest form is 1/3.
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3 years ago
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Uma loja de equipamentos eletrônicos anunciou um celular com duas opções de venda. Na primeira opção, o pagamento pode ser feito
Lena [83]

Responda:

Preço = $ 400

Explicação passo a passo:

Dado que:

Primeira opção :

Pagamento em 5 investimento igual

Segunda opçao :

Pagamento feito em 8 iguais. Investimento

O preço por parcela do primeiro investimento é 30 a mais do que cada um do segundo

Deixe o preço do telefone = p

Valor por prestação = x

Segunda parcela:

Preço = 8x

Primeiro :

Valor por parcela = x + 30

P = 5 (x + 30)

Preço = 5x + 150

Portanto, igualando as duas equações:

8x = 5x + 150

8x - 3x = 150

5x = 150

x = $ 50

Usando qualquer das equações de preço:

Preço = 8x

Preço = 8 * 50

Preço do telefone = $ 400

3 0
3 years ago
What is the simplified form of this expression 7(^3sqrt2x)-3(^3sqrt16x)-3(^3sqrt8x)
trasher [3.6K]

Answer:

<h2>7 \sqrt[3]{2x}  - 6 \sqrt[3]{2x}  - 6x</h2>

Solution,

7( \sqrt[3]{2x} ) - 3( \sqrt[3]{16x} ) - 3( \sqrt[3]{8x} ) \\  = 7 \sqrt[3]{2x}  - 3 \times ( \sqrt[3]{2 \times 2 \times 2 \times 2x}  - 3 \times  \sqrt[3]{2 \times 2 \times 2x}  \\  = 7 \sqrt[3]{2x}  - 3 \times (2 \sqrt[3]{2} x) - 3 \times 2x \\  = 7 \sqrt[3]{2x}  - 3 \times 2 \times  \sqrt[3]{2x}  - 3 \times 2x \\  = 7 \sqrt[3]{2x}  - 6 \sqrt[3]{2x}  - 6x

Hope this helps...

Good luck on your assignment...

7 0
3 years ago
Please help!!
sveta [45]
For this case we have the following equation:
 d =  \sqrt{\frac{3h}{2}}
 Where,
 d: the distance they can see in thousands
 h: their eye-level height in feet
 For Kaylib:
 d = \sqrt{\frac{3(48)}{2}}
 d=\sqrt{3(24)}
 d=\sqrt{72}
 d=6\sqrt{2}
 For Addison:
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 d = \sqrt{\frac{256}{2}}
 d=\sqrt{128}
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 8\sqrt{2} - 6\sqrt{2} = 2\sqrt{2}
 Answer:
 
2\sqrt{2}
 B. 2√2 mi
6 0
3 years ago
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