Answer:
2.8 (from 2.75 because of rounding)
Step-by-step explanation:
2x = -2x + 11
Add 2x on both sides
4x = 11
Divide 4 on both sides
x = 11/4
x = 2.75
Round to nearest tenth
x is about 2.8
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We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:

Where
represents the number of objects/people in the set and
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set


Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru
Answer:
x = 10
Step-by-step explanation:
Use the Pythagorean theorem. The sum of the square of the sides is the square of the hypotenuse.
x² +(√200)² = (√300)²
x² = 300 -200
x = √100 = 10
The length of the unknown side is 10 units.
Answer:
-7
Step-by-step explanation:
16x=-112
x=-112/16
x=-7
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