<span>To solve this equation we
can first assume that both a and b are nonzero real numbers. Hence,
A = 1 b = 1
<span><span>
1.
</span>2 (1) + 1 =
2(1)</span>
<span><span>
2.
</span><span> 2 + 1 = 2: now this a false equation since
there is not equality, the equation cannot retain the equal sign but will
become 2 + 1 > 2. Leaving the relationship unequal.
</span></span>However, the alternative to
this problem is to be b = 0. To oversee the rule in order to solve the equation
retaining it as an “equation”. Further, there is no other solution for this
equation.
A = 1 b = 0
<span>1.
Which
becomes 2(1) + 0 = 2(1)</span>
<span><span>
2.
</span><span> 2 + 0 = 2 :
3. 2 = 2. Here we can observe the
equality. </span></span>
</span>
2-0.5=1.5
3.5-2=1.5
Therefore difference is 1.5=n
1.5n-1 is nth term
When n=20
=29
Answer:
Step-by-step explanation:
The sum if the geometric sequence given by:
an=-2(3)^(n-1)
will be:
when:
n=1
an=-2
when n=2
a2=-6
when n=3
a3=-18
when n=4
a4=-54
when n=5
a5=-162
when n=6
a6=-486
when n=7
a7=-1458
when n=8
a8=-4374
thus the summation of the term will be:
Sn=(-4374+-1458+-486+-162+-54+-18+-6+-2)
Sn=-6560
the answer is -6560
Answer:
<em>The equation will be: 
</em>
Step-by-step explanation:
The number of student tickets that were sold 
and the number of other tickets that were sold 
Student tickets cost $3 a piece and tickets for everyone else cost $5 each.
So, <u>the total cost of</u> 
<u>student tickets</u> 
and <u>the total cost of</u> 
<u>other tickets</u> 
Given that, the drama club sold <u>total $779 worth of tickets</u>.
So, the equation will be:
