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Scilla [17]
3 years ago
8

1/2(4n-8)+10=4(n+5)​

Mathematics
2 answers:
azamat3 years ago
8 0

Answer:multiply both numbers in the parenthesis by the number outside:

2n+4 +10=4n+20

add all like terms

2n+14=4n+20

subtract both sides by 14 and 4

2n-4n = 20 - 14

add or subtract like terms

-2n = 6

divide both sides by -2

n = -3

Step-by-step explanation:

madreJ [45]3 years ago
3 0

Answer:

n= -7

Step-by-step explanation:

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How many minutes are in 5/6, 1/2, and 2/3 of an hour
julia-pushkina [17]
An hour has 60 minutes.

-> 5/6 of 60 minutes
5/6*60
=50

So, 50 minutes

-> 1/2 of 60 minutes
1/2*60
=30

So, 30 minutes

-> 2/3 of 60 minutes
2/3*60
=40

So, 40 minutes.


Hope this helps. If you have any questions, please put them in the comments below.
5 0
3 years ago
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Find the indefinite integral. (remember to use absolute values where appropriate. use c for the constant of integration.) x2 − 2
julsineya [31]
:) Well, I dunno about anyone else but this question makes my head spin!

6 0
3 years ago
6% of what number is 30
uranmaximum [27]
1.8 is 6 percent of 30
4 0
2 years ago
An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s
Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, s=120\ ft/s

The height 'h' of the debris above the ground is given as:

h(t)=-16t^2+120t

As per question, h(t)=56\ ft. Therefore,

56=-16t^2+120t

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0

Using quadratic formula to solve for 't', we get:

t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s

Therefore, the debris will reach a height of 56 ft twice.

When time t=0.5\ s during the upward journey, the debris is at height of 56 ft.

Again after reaching maximum height, the debris falls back and at t=7\ s, the height is 56 ft.

5 0
3 years ago
Help plsssss!!!!!!!!!!!!!
lapo4ka [179]

Answer:

Percent, Part, whole, I am not sure the rest hope this helped though

Step-by-step explanation:

3 0
2 years ago
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