Answer:
Option B. The volume is the product of the area of the base, 2x(2x + 5), and the height, 2x – 3
Step-by-step explanation:
<u><em>The picture of the question in the attached figure</em></u>
we know that
The volume of a rectangular prism is equal to
where
B is the area of the base of the prism
H is the height of the prism
In this problem we have
The area of the base B is equal to
The height H is equal to
therefore
The volume is equal to
The volume is the product of the area of the base, 2x(2x + 5), and the height, 2x – 3
The rate of change of a linear equation (first degree) is equivalent to the slope of a line. Slope is described as the vertical movement (rise) of the line over its horizontal counterpart (run). In determining the rate of change or slope (m) given 1 data point (x',y'), point-slope form is applicable. Point-slope form is: (y-y') = m (x-x'). Substitute the given point (-5,-1) in the equation. By substitution, [y-(-1)] = m [x-(-5)]. Re-arranging the equation, the rate of change or slope is, m = (y+1)/(x+5).
Answer:
≈23.6 kg left.
Step-by-step explanation:
For determining this, we can simply use an exponential decay equation representing this scenario:
a: the initial amount
t: the amount of time
h: the half life
Now, substitute the numbers into the equation:
Now, solve this equation:
Use a calculator to solve for y:
y= 200(0.118)
y≈23.6 kg left.
Answer: 
Step-by-step explanation:
For this exercise you need to remember that a Square is defined as a Quadrilateral whose sides are equal in lenght and all its interios angles measure 90 degrees.
Based on that definition, and observing the squarE given in the picture attached, you can write the following equation:
Then, you need to solve for the variable "x" in order to find its value. You get that this is:
Now, knowing the value of "x" you can susbstitute it into any expression that represents the side of the square, and then you must evaluate in order to find the lenght of the side.
You get:
1/3x - 2 = 1/4x + 11....it looks to me like one y was subbed in for another...
ur 2 equations are :
y = 1/3x - 2 and y = 1/4x + 11...but we need them in standard form...
y = 1/3x - 2
-1/3x + y = -2 ..multiply by 3
-x + 3y = -6.....or 3y - x = -6 <==
y = 1/4x + 11
-1/4x + y = 11 ...multiply by 4
-x + 4y = 44 or 4y - x = 44 <==
