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3 years ago

Which basic construction is shown here?

Mathematics

2 answers:

Soloha48 [4]3 years ago

8 0

Answer:

The correct answer is B) bisect a line segment

Step-by-step explanation:

By noting that RP and PS are the same distance, we know that segment has been cut in half (or bisected). As a result, we know the constructed line of AP is a bisector.

bija089 [108]3 years ago

6 0

Construct a parallel line

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3) This is a writer's opinion or way of seeing an issue.

Ivahew [28]

Answer:

the word is viewpoint

Step-by-step explanation:

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3 years ago

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The length of a couch is 200 centimeters. This is 16 centimeters less than 3 times the width of a matching chair. How wide is th

Snowcat [4.5K]

Answer:

i think the answer is 72

Step-by-step explanation:

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3 years ago

Y''+y'+y=0, y(0)=1, y'(0)=0

mars1129 [50]

Answer:

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Step-by-step explanation:

A second order linear , homogeneous ordinary differential equation has form $ay''+by'+cy=0$ .

Given: $y''+y'+y=0$

Let $y=e^{rt}$ be it's solution.

We get,

$\left ( r^2+r+1 \right )e^{rt}=0$

Since $e^{rt}\neq 0$ , $r^2+r+1=0$

{ we know that for equation $ax^2+bx+c=0$ , roots are of form $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ }

We get,

$y=\frac{-1\pm \sqrt{1^2-4}}{2}=\frac{-1\pm \sqrt{3}i}{2}$

For two complex roots $r_1=\alpha +i\beta \,,\,r_2=\alpha -i\beta$ , the general solution is of form $y=e^{\alpha t}\left ( c_1\cos \beta t+c_2\sin \beta t \right )$

i.e $y=e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Applying conditions y(0)=1 on $e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$ , $c_1=1$

So, equation becomes $y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

On differentiating with respect to t, we get

$y'=\frac{-1}{2}e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )+e^{\frac{-t}{2}}\left ( \frac{-\sqrt{3}}{2} \sin \left ( \frac{\sqrt{3}t}{2} \right )+c_2\frac{\sqrt{3}}{2}\cos\left ( \frac{\sqrt{3}t}{2} \right )\right )$

Applying condition: y'(0)=0, we get $0=\frac{-1}{2}+\frac{\sqrt{3}}{2}c_2\Rightarrow c_2=\frac{1}{\sqrt{3}}$

Therefore,

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

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3 years ago

What is the volume of shed B?

skelet666 [1.2K]

Both the length and width of shed A are 6 feet.
I multiplied 6 by 2 and got 12.
My new equation is 12 × 12 × 8....

Which is 1,152. The answer is H.

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3 years ago

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Bernite is selling candy bars for a school fundraiser. The school paid $20.00 for a box of 15 king-size candy bars and Bernite s

irina1246 [14]

Answer:

Step-by-step explanation:

candy sold vs money earned

money earned = 2 dollars * number of bars sold- cost of bars

money earned = 2 b -20

this is an equation of a line

(y= 2x-20)

A.The relationship is linear true

B.The relationship is nonlinear false

C.The relationship is always results in a negative profit false

it crosses the x axis at 10 candy bars

D.The relationship always result in a positive profit false

it crosses the x axis at 10 candy bars

E.The relationship is proportional false

F.The relationship is non-proportional true it is a line that does not cross the origin

1jaiz4 and 21 more users found this answer helpfulcandy sold vs money earned

money earned = 2 dollars * number of bars sold- cost of bars

money earned = 2 b -20

this is an equation of a line

(y= 2x-20)

A.The relationship is linear true

B.The relationship is nonlinear false

C.The relationship is always results in a negative profit false

it crosses the x axis at 10 candy bars

D.The relationship always result in a positive profit false

it crosses the x axis at 10 candy bars

E.The relationship is proportional false

F.The relationship is non-proportional true it is a line that does not cross the origin

3 0

2 years ago