2(-3n-5)-5(4n-8)
(-6n-10)+(-20n+40)
-26n-30
-x^3 I think is the answer
Answer:
126
Step-by-step explanation:
Let x be the missing length
The triangles are similar:
● UE/140 = 45/x
From the graph we deduce that:
● UE = 140 - 90 = 50
Replace UE by its value
● 50/ 140 = 45/x
Switch x and 50
● x / 140 = 45/50
45/50 is 9/10 wich is 0.9
● x/140 = 0.9
Multiply 0.9 by 140
● x = 140 × 0.9
● x = 126
Answer:
1,2. 6.0
Step-by-step explanation:
That is the answer
The <em>correct answers</em> are:
C) No: we would need to know if the vertex is a minimum or a maximum; and
C)( 0.25, 5.875).
Explanation:
The domain of any quadratic function is all real numbers.
The range, however, would depend on whether the quadratic was open upward or downward. If the vertex is a maximum, then the quadratic opens down and the range is all values of y less than or equal to the y-coordinate of the vertex.
If the vertex is a minimum, then the quadratic opens up and the range is all values of y greater than or equal to the y-coordinate of the vertex.
There is no way to identify from the coordinates of the vertex whether it is a maximum or a minimum, so we cannot tell what the range is.
The graph of the quadratic function is shown in the attachment. Tracing it, the vertex is at approximately (0.25, 0.5875).