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DIA [1.3K]
3 years ago
11

Let g and f be two functions defined by

Mathematics
1 answer:
aniked [119]3 years ago
6 0

Answer:

g/f(-3) = (1/29) * (-5+x)(2+x)

2/9 is NOT in the domain of g/f

Step-by-step explanation:

First we will calculate f(-3):

f(-3) = 2-9*(-3) = 2-(-27) = 2+27 = 29

Therefore, g/f(-3) = (1/29) * (-5+x)(2+x)

Now we will find the values that are not in the domain of g/f:

g/f = [(-5+x)(2+x)]/(2-9x)

The denominator of g/f should not be equal to zero, hence:

2-9x ≠ 0 ⇒ 2≠9x⇒x≠2/9

Therefore, 2/9 is NOT in the domain of g/f

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