All categories

2 years ago

Given a circle with a radius of 4, which is the circumference? A. 4 B. 6 C. 8 D. 12

Mathematics

2 answers:

kogti [31]2 years ago

7 0

Answer:

For Plato users the answer is 8 pi , mark me the brainliest

Step-by-step explanation:

o-na [289]2 years ago

5 0

Circumference = 2 x Pi x R

if we use 3.14 as pi, you would do 2 x 3.14 x 4, which would equal 25.12, i’m not sure if it was meant to be rounded to 25, but none of the multiple choice answers would be correct

You might be interested in

A student answers 160 of 200 questions on an exam correctly. What percent of the questions did he answer correctly?

Alexandra [31]

Dive correct answers by total questions:

160/200 = 0.80

Multiply by 100 to get percent:

0.80 x 100 = 80%

5 0

2 years ago

Read 2 more answers

What is the slope and y-intercept of the linear equation y = 5x − 4? <br> M= ? <br> B= ?

Feliz [49]

Answer:

M=5

B= -4

Step-by-step explanation:

y = mx + b

7 0

3 years ago

Read 2 more answers

How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?

MrRissso [65]

$\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3} \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(3x)^{3 \times \frac{5}{3} }}{(2y^3)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}$

Now, If the exponent was negative like you asked....

$\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}$

5 0

3 years ago

Marvin used a customary unit of measure to estimate the weight of a watermelon he grew in his backyard what could the estimated

Andrej [43]

Answer:

Usually pounds (lb) .About an an average of 20 to 25 pounds (lbs)

Step-by-step explanation:

Since Marvin uses Customary units, and considering the Watermelon.

Pounds, He could estimate based on average of 20 to 25 pounds.

He could choose another customary units, but it wouldn't be practical and unusual to say a watermelon of 160 quarters, also it would leave all the listeners without parameters.

So, definitely pounds.

3 0

3 years ago

Every whole number is a real number . <br> True or false

grandymaker [24]

True. No imaginary number is considered "whole", all whole numbers are rational and real.

8 0

2 years ago

Read 2 more answers