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QveST [7]
3 years ago
8

In a school with 117 seventh-grade students and about 29 students per class, the number of seventh-grade classes is about

Mathematics
2 answers:
Reil [10]3 years ago
8 0

Answer:

4

Step-by-step explanation:

In a school with 117 seventh-grade students and about 29 students per class, the number of seventh-grade classes is about.

117 / 29 = 4.03

rounded is 4

notka56 [123]3 years ago
5 0

Answer - 4 classes

117 ÷ 29 = 4.03...

That is the answer. hope this helps.

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Root 3 cosec140° - sec140°=4<br>prove that<br><br>​
Lorico [155]

Answer:

Step-by-step explanation:

We are to show that \sqrt{3} cosec140^{0} - sec140^{0} = 4\\

<u>Proof:</u>

From trigonometry identity;

cosec \theta = \frac{1}{sin\theta} \\sec\theta = \frac{1}{cos\theta}

\sqrt{3} cosec140^{0} - sec140^{0} \\= \frac{\sqrt{3} }{sin140} - \frac{1}{cos140} \\= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\

From trigonometry, 2sinAcosA = Sin2A

= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\\\=  \frac{\sqrt{3}cos140-sin140 }{sin280/2}\\=  \frac{4(\sqrt{3}/2cos140-1/2sin140) }{2sin280}\\\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{sin280}\\since sin420 = \sqrt{3}/2 \ and \ cos420 = 1/2  \\ then\\\frac{4(sin420cos140-cos420sin140) }{sin280}

Also note that sin(B-C) = sinBcosC - cosBsinC

sin420cos140 - cos420sin140 = sin(420-140)

The resulting equation becomes;

\frac{4(sin(420-140)) }{sin280}

= \frac{4sin280}{sin280}\\ = 4 \ Proved!

3 0
3 years ago
Select all the expressions which are equivalent to<br> -4/3p - 2/5
AVprozaik [17]

Answer

-2/5 -4/3 p and -4/3p+ (-2/5)

Step-by-step explanation:

those two are the only answers that has both parts of the expressions as negative.

6 0
3 years ago
Please help asap! if you could also explain how you did it so I can answer the other questions by myself
Usimov [2.4K]

Answer:

Step-by-step explanation:

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8 0
3 years ago
Find the area of the largest square contained by a circle of radius r = 1cm. Explain your answer and justify that it is correct.
Elena-2011 [213]

Answer:

2 square cm

Step-by-step explanation:

Given :

A square is inscribed in a circle whose radius is r = 1 cm

Therefore, the diameter of the circle is 2 r = 2 x 1

                                                                      = 2 cm.

So the diagonal of the square is 2r.

Using the Pythagoras theorem, we find each of the side of the triangle is $r \sqrt 2$.

Therefore, the area of the square is given by $\text{(side)}^2$

                                                                         = $(r\sqrt 2)^2$

                                                                         $= 2 r^2$

                                                                         $= 2 (1)^2$

                                                                         $=2 \ cm^2$

Hence the area of the largest square that is contained by a circle of radius 1 cm is 2 cm square.

7 0
3 years ago
Write 7.12 as a mixed number in simplest form.
andrezito [222]

Answer:

7 3/25

Step-by-step explanation:

8 0
3 years ago
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