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3 years ago

Help me please assap

Mathematics

1 answer:

Reil [10]3 years ago

5 0

Answer: G

<u>Step-by-step explanation:</u>

(x, y) → ( $\frac{1}{8}x$ , $\frac{1}{8}y$ )

means that the new quadrilateral will be $\frac{1}{8}$ the size of the original quadrilateral, so it will be smaller because the it maps to a fraction that is less than 1.

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How many numbers are written from n to k, including n and k?

Rainbow [258]

Answer:

k-n+1

Step-by-step explanation:

How many numbers are written from n to k

Lets look at a smaller example with real number

Lets go from 3 to 8

3 4 5 6 7 8

There are 6 numbers

We take 8 -3 = 5, but we include the number 3 so we add it back in +1

5+1 =6

Lets look at a larger example

2 to 11

2,3,4,5,6,7,8,9,10,11

There are 10 numbers

11-2 =9 but we have to add back in the first number

9+1 =10

Now we are going from n to k

k-n = k-n, but we have to add back in the first number

k-n+1

7 0

3 years ago

A bee flies at 9 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for 17 minutes, and then

antiseptic1488 [7]

Answer:

B) 864 feet

Step-by-step explanation:

Here's my answer. I'm not too sure how to form the equation though. Hope this helps :)

5 0

3 years ago

One flight of stairs has a slope of 3/4 , while another flight of stairs contains points (-2,3) and (14, 15). Would these be par

shusha [124]

Answer:

Perpendicular

Step-by-step explanation:

m=y2-y1/x2-x1

m=15-3/14-(-2)

m=3/4

7 0

3 years ago

What percent of 80 is 90

Serhud [2]

$\text{What percent of 80 is 90?}\\\\\text{Calculate what fraction of the number 90 is 80}\\\\\dfrac{80}{90}=\dfrac{8}{9}\\\\\text{Convert it to percent}\\\\\dfrac{8}{9}\cdot100\%=\dfrac{800}{9}\%=88\dfrac{8}{9}\%\\\\Answer:\ \boxed{80\ is\ 88\dfrac{8}{9}\%\ of\ 90}$

8 0

3 years ago

Express this to single logarithm

zzz [600]

Answer: $\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)$

We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.

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Explanation:

It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.

I'm going to use these three log rules, which apply to any base.

log(A) + log(B) = log(A*B)
log(A) - log(B) = log(A/B)
B*log(A) = log(A^B)

From there, we can then say the following:

$\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}$

8 0

3 years ago